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miskamm [114]
3 years ago
9

Write the equation of a line that passws through the point (1,7) and is perpendicular to y=1/2x-5

Mathematics
1 answer:
Firdavs [7]3 years ago
5 0

Answer:

y=-2x+5

Step-by-step explanation:

For one line to be perpendicular to another, their slopes must multiply to -1. So, we really want the line with slope $-1/(1/2)$ = -2$ that passes through the point (1, 7).

Recall the point-slope form of a line. If you have a point $(x_{1}, y_{1})$ and a slope m, the line through that point with the given slope is $y-y_{1}=m(x-x_{1})$. Plugging in our given point and slope gives our line: y-7=-2(x-1)(point-slope form).

We can convert this line to slope-intercept form, the most common form by expanding the right side and adding 7 to get y by itself:

y-7=-2x+2

y=-2x+5

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Elaine has a piece of wire that is 2.16 meters long.Dikembe has a piece of wire that is 2.061 meters long. whose piece of wire i
vesna_86 [32]
Elaine's piece is bigger because when you look at the tenths place, you can see that 1 is bigger than 0.
4 0
3 years ago
Read 2 more answers
AB=2y+1, BC=y+1,CD=7x-3,DA=3x what is x and y
sattari [20]
I attached the picture associated with this question.

Answer:
x = 2
y = 5

Explanation:
ABCD is a parallelogram. This means that each two opposite sides are equal.
This means that:
1- AB = CD
2y + 1 = 7x - 3 ...........> equation I
2- AD = BC
3x = y + 1
This can be rewritten as:
y = 3x - 1............> equation II

Substitute with equation II in equation I and solve for x as follows:
2y + 1 = 7x - 3 ...........> equation I
2(3x - 1) + 1 = 7x - 3
6x - 2 + 1 = 7x - 3
6x - 1 = 7x - 3
7x - 6x = -1 + 3
x = 2

Substitute with x in equation I to get y as follows:
y = 3x - 1
y = 3(2) - 1
y = 6 - 1
y = 5

Hope this helps :)

3 0
3 years ago
9(y-4) -3y = 2(3y-2 need solved as fast as possible
Vlad [161]

Step-by-step explanation:

did you give us all the information ? the equating looks cut off.

so, from what I can see we have

9(y-4) - 3y = 2(3y-2)

let's try :

9y - 36 - 3y = 6y - 4

0 = 32

so, no, this can't be it. this does not have a solution. you must have cut off some additional information.

7 0
3 years ago
Use the difference of squares identity to write this polynomial expression in factored form:
s344n2d4d5 [400]
9x^2-49
It equals:
(3x+7)(3x−7)

Hope this helps!
6 0
3 years ago
Which of the following points below represents (- 2, - (5pi)/4) the polar grid?
Maru [420]

Answer:

Well, when we have a point in rectangular coordinates (x, y) and we want to write it in polar coordinates (r, θ) the rule we use is:

r = √(x^2 + y^2)

θ = Atg(Iy/xI) + 90°*(n - 1)

where n is number of the quadrant where our point is.

For example, if we are on the second quadrant, we use n = 2.

Now, if instead, we have the point (r, θ) and we want to rewrite it in rectangular coordinates, then the transformation is:

x = r*cos(θ)

y = r*sin(θ)

Now we have the point (- 2, -(5pi)/4) because the first part is negative, this number can not be in polar coordinates (r can not be negative) then we have:

x = -2

y = -(5*pi)/4

Using the first relation, we can find that:

r = √( (-2)^2 + (-5*3.14/4)^2) = 4.4

(rememer that the point (- 2, -(5pi)/4) is on the third quadrant, then we will use n = 3.)

θ = Atg(-(5*pi)/4/-2) + 90°*(3 - 1)= Atg((5*pi)/2) + 180° = 82.7° + 180° = 262.7°

Then the point that represents  (- 2, - (5pi)/4) in polar coordinates is the point:

(4.4, 262.7°)

If instead of degrees, the angle part is written in radians, we have:

180° = 3.14 radians.

262.7° = x radians.

then:

x/3.14 = (262.7)/180

x =  3.14*(262.7)/180 = 4.58 radians.

then the point will be:

(4.4, 4.58 radians)

7 0
3 years ago
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