The area is that of two 20 yd squares and one 20 yd circle.
.. A = 2*(20 yd)^2 +(π/4)*(20 yd)^2
.. = (2 +π/4)*(400 yd^2)
.. = (800 +100π) yd^2
.. ≈ 1114.16 yd^2
The perimeter is that of a 20 yd circle and 80 yd more.
.. P = π*20 yd + 80 yd
.. ≈ 142.83 yd
Answer:
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Step-by-step explanation:
Hello from MrBillDoesMath!
Answer:
-1/16
Discussion:
Rewrite
((1/4 + 1/x)/(4+x)) as
(1/4 + 1/x) * (1/(4+x)) = => put num. over common denom,
( (x+4)/4x) * (1/(4+x)) = => cancel (x+4) from num. and denom.
(1/4x)
So as x ->-4, (1/4x) approaches ( 1/ ( 4 * (-4) ) ) = -1/16
Thank you,
MrB
Answer:
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