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Gelneren [198K]
3 years ago
14

George ate 2/ 3 of a container of Chinese food. Silvia ate 1/ 5 of the same container of Chinese food. What fraction of the cont

ainer of Chinese food did they eat together?
Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
4 0

Answer: Fraction of the container of Chinese food they eat together = \dfrac{13}{15}

Step-by-step explanation:

Given, Fraction of Chinese food eaten by George = \dfrac23

Fraction of Chinese food eaten by Silvia = \dfrac15

Fraction of the container of Chinese food they eat together = \dfrac23+\dfrac15 =\dfrac{2\times5+3\times1}{3\times5}

=\dfrac{10+3}{15}=\dfrac{13}{15}

Fraction of the container of Chinese food they eat together = \dfrac{13}{15}

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Answer:

x=64

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Step-by-step explanation:

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x=24-4y/3 96-12y\3+3y=22

x=24-4(54)/3

x=-64 96/3-22=3y/3

y=54

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2 years ago
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iren2701 [21]
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Identify thenull hypothesis, alternative hypothesis, test statistic, P-value or critical value(s), then state the conclusion abo
miv72 [106K]

Answer:

Step-by-step explanation:

This is a test of 2 population proportions. Let m and w be the subscript for men and women players. The population proportions would be pm and pw

Pm - Pw = difference in the proportion of male and female players.

The null hypothesis is

H0 : pm = pw

pm - pw = 0

The alternative hypothesis is

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Where

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For men,

xm = 1027

nm = 2441

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For women,

xw = 509

nw = 1273

Pw = 509/1273 = 0.4

The pooled proportion, pc is

pc = (xm + xw)/(nm + nw)

pc = (1027 + 509)/(2441 + 1273) = 0.41

1 - pc = 1 - 0.41 = 0.59

z = (Pm - Pw)/√pc(1 - pc)(1/nm + 1/nw)

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Area to the right from the normal distribution table is

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3 0
3 years ago
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3 years ago
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3 years ago
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