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tamaranim1 [39]
3 years ago
5

1. What is an extraneous solution of an equation?

Mathematics
1 answer:
Vadim26 [7]3 years ago
6 0
“Extraneous solutions are not solutions at all. They arise from outside the problem, from the method of solution. They are extraneous because they are not solutions of the original problem. ... To tell if a "solution" is extraneous you need to go back to the original problem and check to see if it is actually a solution.”

Basically, they are an answer you get when you solve a problem, but they don’t actually make the equation true so you disregard it.
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A factory packed 9600kg of flour in to small bags and large bags. Each small bag contained 3kg of flour and each large bag conta
yawa3891 [41]

Answer:

696 large bags of flour were packed.

Step-by-step explanation:

Let large bags of flour be 'y'

Let small bags of flour be 'x'. That is x=2040 (according to the question)

(3 \times x) + (5 \times y) = 9600

(3 \times 2040) + ( 5 \times y) = 9600

(6120) + (5 \times x) = 9600

(5 \times x) = 9600 - 6120

(5 \times x) = 3480

x = 3480  \div 5

x = 696

HOPE IT HELPS

#PEACE

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3 years ago
A soup can in the shape of a cylinder is 4 inches tall and has a radius of 2 inches
svlad2 [7]
The volume is around 50.27

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the perimeter 25.13
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3 years ago
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In four years, 40% of a radioactive element decays. Find its half-life. Round to one decimal place.
White raven [17]

To find the answer, use k = \frac{2.303 }{ 4} (log\frac {100 }{ 40}) , and then use the equation t=\frac{.693}{k} To find it's half life.

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4 years ago
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Write an equation for a circle with a diameter that has endpoints at (–10, 1) and (–8, 5). Round to the nearest tenth if necessa
satela [25.4K]

The standard form for the equation of a circle is :

<span><span><span> (x−h)^</span>2</span>+<span><span>(y−k)^</span>2</span>=<span>r2</span></span><span> ----------- EQ(1)
</span><span> where </span><span>handk</span><span> are the </span><span>x and y</span><span> coordinates of the center of the circle and </span>r<span> is the radius.
</span> The center of the circle is the midpoint of the diameter.

 So the midpoint of the diameter with endpoints at (−10,1)and(−8,5) is :

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 So the point (−9,3) is the center of the circle.

  Now, use the distance formula to find the radius of the circle:

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 Subtituting h=−9, k=3 and r=√5 into EQ(1) gives :

 (x+9)^2+(y−3)^2=5

7 0
3 years ago
Consider the following sets:
bagirrra123 [75]
U = {points on the coordinate plane}
A = {solutions to the equation y = 2x + 5}
B = {points on the line y = mx}

Value of the slope m so that  {2x + 5} ∩ {mx} =Ф
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y = 2x+5 and y = 2x are PARALLEL


4 0
3 years ago
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