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tamaranim1 [39]

3 years ago

5

1. What is an extraneous solution of an equation?

1 answer:

Vadim26 [7]3 years ago

6 0

“Extraneous solutions are not solutions at all. They arise from outside the problem, from the method of solution. They are extraneous because they are not solutions of the original problem. ... To tell if a "solution" is extraneous you need to go back to the original problem and check to see if it is actually a solution.”

Basically, they are an answer you get when you solve a problem, but they don’t actually make the equation true so you disregard it.

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Simplify the expression <br> 7x/9x

pantera1 [17]

<span>7x/9x = 7/9

hope it helps</span>

4 0

3 years ago

nikitadnepr [17]

Answer:

The value of x is $\frac{-2}{5}$ .

Step-by-step explanation:

Given expression is:

$\frac{2}{3}(x-2)=4x$

We have to solve this for x.

First we will multiply both sides of the equation by 3

$3*\frac{2}{3}(x-2)=4x*3$

2(x-2) = 12x

2x-4=12x

Now we will be subtracting 2x from both sides of the equation

2x-2x-4=12x-2x

-4=10x

10x=-4

Dividing both sides by 10

$\frac{10x}{10}=\frac{-4}{10}\\\\x=\frac{-2}{5}$

Hence,

The value of x is $\frac{-2}{5}$ .

8 0

3 years ago

Multiply and simplify: 2a(7a^a-3a+9)

Inessa [10]

If a were 1, The answer would be:

26

Hope this helps:)

4 0

3 years ago

Read 2 more answers

Find the values of a, b, and c.

Hunter-Best [27]

<span>a = 36, b = 118, c = 62

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4 0

3 years ago

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Select the correct trigonometric ratios for angle 0

ratelena [41]

Answer:

A, D, and F

Step-by-step explanation:

First off, we're not given the hypotenuse's length, so let's use the Pythagorean Theorem to find it:

$1^2+3^2=c^2\\1+9=c^2\\10=c^2\\c=\sqrt{10}$

With that, we can refer to SOH-CAH-TOA to help us find sine, cosine, and tangent:

SOH (Sine = Opposite/Hypotenuse)

$\sin{\theta}=1/\sqrt{10}=\sqrt{10}/10$

CAH (Cosine = Adjacent/Hypotenuse)

$\cos{\theta}=3/\sqrt{10}=3\sqrt{10}/10$

TOA (Tangent = Opposite/Adjacent)

$\tan{\theta}=1/3$

From this, we can see that A matches up with sine, and we can eliminate B and C.

Cosecant, secant, and cotangent are all reciprocals of the three basic trig ratios:

$\csc{\theta}=1/\sin{\theta}=\sqrt{10}\\\sec{\theta}=1/\cos{\theta}=\sqrt{10}/3\\\cot{\theta}=1/\tan{\theta}=3$

D matches with cosecant, and F matches with cotangent, so the correct trig rations for θ are A, D, and F.

3 0

3 years ago