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Zolol [24]
4 years ago
14

Can somebody please help me on this problem? thanks.

Mathematics
2 answers:
Sergio039 [100]4 years ago
6 0
90 - (x + 54) - 5x
= 90 - x - 54 - 5x
= 90 - 54 - 6x
= 36 - 6x
6x = 36
x = 36/6
x = 6
Natali5045456 [20]4 years ago
6 0
The angle on the bottom is a straight angle so its 180˚
The angles to solve are complementary (adding up to 90˚)

5x+x+54=90
6x+54=90
6x=36
x=6
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Simplify negative 3 and 1 over 9 − negative 8 and 1 over 3.
VMariaS [17]

Answer:

-11 4/9

Step-by-step explanation:

-3 1/9 minus 8 1/3 with common denominators would be -3 1/9 minus 8 3/9, and that would be -11 4/9.

6 0
3 years ago
Which of the following are ordered pairs for the equation y = 1/3x + 1?
andreyandreev [35.5K]

Answer:

The second answer choice; (0,1) (3,2) (6,3) is your answer.

Step-by-step explanation:

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6 0
3 years ago
Pls help solve question 3
Lelu [443]

Answer:

If m is the midpoint of ab it means am is equal to mb

am = 3x + 8 and mb = 6x-4

and ab  = am + mb

first find the value of x by using am = mb

3x + 8 = 6x - 4

8 + 4 = 6x - 3x

12 = 3x

x = 4

ab = 3 (4) + 8

= 12 + 8 = 20 = mb

ab = am + mb

= 20 + 20

40

so, the value of ab is 40

4 0
3 years ago
Can the following expressions be written in a simpler forms? If yes, write an expression for each problem. If not, explain why w
Alona [7]

Answer:

Both of them can be simplified.

Recall that 4 = 2^2.

2^7 / 4^2 = 2^7 / (2^2)^2 = 2^7 / 2^4 = 2^(7-4) = 2^3 = 8

Similarly, 2^7 / 2^4 = 2^(7-4) = 2^3 = 8

The answers to both exercises are 8.

6 0
3 years ago
Question: What is the volume of the box? Explain how you found your solution.
Vikki [24]

The volume of the box is 100 cubic meter.

Step-by step explanation:

Given data:

Length of the box = 10 m

Width of the box = 5 m

Height of the box = 2 m

<u>To find the volume of the box:</u>

Volume of the box = length × width × height

                               = 10 m × 5 m × 2 m

                               = 100 cubic meter

Hence the volume of the box is 100 cubic meter.

8 0
4 years ago
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