We are given the points
<span>(0,-4),(1,0),(2,2)
The standard form a quadratic function (in terms of x) is
y = Ax2 + Bx + C
Subsitute the points
-4 = 0 + 0 + C
C = -4
0 = A + B - 4
2 = 4A + 2B - 4
Solve for A and B
A = -1
B = 5
The function is
y = -x2 + 5x - 4</span>
Answer:
Step-by-step explanation:
b
Answer:
not sure if it's ryt but I think it's A
Answer:
Answer: y=2x+13.
Step-by-step explanation:
Your input: find the equation of the line perpendicular to the line y=5/2−x/2 passing through the point (−4,5).
The equation of the line in the slope-intercept form is y=5/2−x/2.
The slope of the perpendicular line is negative inverse: m=2.
So, the equation of the perpendicular line is y=2x+a.
To find a, we use the fact that the line should pass through the given point: 5=(2)⋅(−4)+a.
Thus, a=13.
Therefore, the equation of the line is y=2x+13.
Answer: y=2x+13.
<h3>Corresponding angles =
angle 1 and angle 5</h3>
They are on the same side of the transversal cut (both to the left of the transversal) and they are both above the two black lines. It might help to make those two black lines to be parallel, though this is optional.
Other pairs of corresponding angles could be:
- angle 2 and angle 6
- angle 3 and angle 7
- angle 4 and angle 8
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<h3>Alternate interior angles = angle 3 and angle 5</h3>
They are between the black lines, so they are interior angles. They are on alternate sides of the blue transversal, making them alternate interior angles.
The other pair of alternate interior angles is angle 4 and angle 6.
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<h3>Alternate exterior angles = angle 1 and angle 7</h3>
Similar to alternate interior angles, but now we're outside the black lines. The other pair of alternate exterior angles is angle 2 and angle 8
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<h3>Same-side interior angles = angle 3 and angle 6</h3>
The other pair of same-side interior angles is angle 4 and angle 5. They are interior angles, and they are on the same side of the transversal.
