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Alborosie
3 years ago
5

Suppose you have 48 feet of fencing to enclose a rectangular dog pen. The function

Mathematics
1 answer:
Rufina [12.5K]3 years ago
5 0

Take first derivative of area function and set it to zero

da/dx=24 - 2x=0

Now it is set to zero add -2x to both side

24 - 2x = 0

24 = 2x

Now divide by 2 in both sides

12 = Width

Your width now is 12

Plug 12 into you equation like this:

24 (12) - 12^2= A

288 - 144 = A

144 = Area

144 feets is the maximum area using the width 24


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Find the unit rate for 1/2 mile in 3/10 hour
babunello [35]

Answer:

1 mile for every 0.6 hours

Step-by-step explanation:

0.5 x 2 = 1

3/10 x 2 = 6/10

2 miles = 1.2 hours

4 0
3 years ago
I need help. Part A: Create a five-number summary and calculate the interquartile range for the two sets of data. (5 points)
Dahasolnce [82]

Five number summary and IQR of both the data sets are different.

For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5

For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5

No, the box plots are not symmetric.

Part A:

The given data sets are

School A : 9,14,15,17,17,7,15,6,6

School B : 12,8,13,11,19,15,16,5,8

Arrange the data in ascending order.

School A : 6,6,7,9,14,15,15,17,17

School B : 5,8,8,11,12,13,15,16,19

Divide each data set into four equal parts.

School A : (6,6),(7,9),14,(15,15),(17,17)

School B : (5,8),(8,11),12,(13,15),(16,19)

For school A:

Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17

The interquartile range of the data is

For school B:

Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19

IQR=Q_3-Q_1\\     =Q_3-Q_1\\     =16-6.2\\     =9.5

The interquartile range of the data is

IQR=Q_3-Q_1\\     =Q_3-Q_1\\     =15.5-8\\     =7.5

Part B:

The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data sets are different.

To learn more about the symmetric visit:

brainly.com/question/1002723

#SPJ1

6 0
2 years ago
Calculate the loss on selling 50 shares of stock originally bought at 133/4 and sold at 12.
Anarel [89]
Here is the solution of the given problem above:
The first thing we should do is to multiply 50 and 13 3/4 
13 3/4 is equivalent to 13.75 .
So, we then multiply 
50 x 13.75  and we get 687.50.
so, $687.50 was the amount spent on the stock. 
Now, lets find out how much they sold them for:
What we do is multiply 12 and 50 
50 x 12 would be 600
We can find out the loss by subtracting 
$687.50 - $600 and that gives us $ 87.50.
Therefore, the amount that is loss in selling is $87.50. The correct answer would be option B. Hope this answer helps.
5 0
3 years ago
Read 2 more answers
Abby works in the sales department. This month the company is offering a 3-week paid vacation to every employee who sells 230% o
Doss [256]
Multiply 48,000 by 2.3 to get 110,400
She needs to sell $110,400 products next month
8 0
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Please help !!! :(<br> 1 and 2 form a linear pair, if the measure of 1 is 113 find the measure of 2
anzhelika [568]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
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