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bulgar [2K]
2 years ago
8

I need help. Part A: Create a five-number summary and calculate the interquartile range for the two sets of data. (5 points)

Mathematics
1 answer:
Dahasolnce [82]2 years ago
6 0

Five number summary and IQR of both the data sets are different.

For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5

For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5

No, the box plots are not symmetric.

Part A:

The given data sets are

School A : 9,14,15,17,17,7,15,6,6

School B : 12,8,13,11,19,15,16,5,8

Arrange the data in ascending order.

School A : 6,6,7,9,14,15,15,17,17

School B : 5,8,8,11,12,13,15,16,19

Divide each data set into four equal parts.

School A : (6,6),(7,9),14,(15,15),(17,17)

School B : (5,8),(8,11),12,(13,15),(16,19)

For school A:

Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17

The interquartile range of the data is

For school B:

Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19

IQR=Q_3-Q_1\\     =Q_3-Q_1\\     =16-6.2\\     =9.5

The interquartile range of the data is

IQR=Q_3-Q_1\\     =Q_3-Q_1\\     =15.5-8\\     =7.5

Part B:

The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data sets are different.

To learn more about the symmetric visit:

brainly.com/question/1002723

#SPJ1

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OPTIONS:

A. The interquartile range of the trail mix data is greater than the range of the cracker data.

B. The value 70 is an outlier in the trail mix data.

C. The upper quartile of the trail mix data is equal to the maximum value of the cracker data.

D. The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.

Answer:

D.

Step-by-step explanation:

With the given information about how the box plot looks like, let's examine each option to see if they are true or not.

<u><em>Option A: "The interquartile range of the trail mix data is greater than the range of the cracker data."</em></u>

The interquartile range of trail mix data = 105 - 90 = 15

Range of cracker data = 100 - 70 = 30

Option A is NOT TRUE.

<u><em>Option B: "The value 70 is an outlier in the trail mix data.</em></u>"

This is NOT TRUE. There are not outliers as 70 is the minimum value if the ranges of the data set for the trail mix.

<em><u>Option C: "The upper quartile of the trail mix data is equal to the maximum value of the cracker data."</u></em>

Upper quartile of the trail mix data = 105

Max value of cracker data = 100

This statement is NOT TRUE.

<em><u>Option D: "The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers."</u></em>

The greater the range value, the greater the variation. Thus,

Range value of the trail mix data = 115 - 70 = 45

Range value of the cracker data = 100 - 70 = 30

This is statement is correct because trail mix data have a greater range value, hence, it has a greater variation in the number of calories.

6 0
3 years ago
Read 2 more answers
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