W=33/8.7
w=3.79
i believe this is the answer
From Newton’s Second Law of Motion, the force needed to accelerate a moving object of mass m at acceleration a is given by ;
F = ma
In this case, m = 5kg, a = 6m/s^2 and we want to find F
F = 5 x 6
F = 30N
Therefore, a force of 30N is needed to accelerate a 5kg object at 6m/s^2.
Answer:
B
Step-by-step explanation:
The zeros ( where the graph crosses the x- axis ) are x = 2 and x = 6
The corresponding factors are (x - 2) and (x - 6) and the equation is the product of the factors, so
y = (x - 2)(x - 6) ← expand using Foil
y = x² - 8x + 12 → B
Hi there!
x - 3y = 9
x = 9 + 3y
-4x + y = 8
-4(9+3y) + y = 8
-36 - 12y + y = 8
-36 - 11y = 8
-11y = 44
-y = 4
y = -4
x - 3y = 9
x - 3(-4) = 9
x + 12 = 9
x = 21
So, your answers are y = -4 and x = 21.
Hope this helps!
