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3 years ago

4.185 divided by 0.93 rounded

Mathematics

1 answer:

mr Goodwill [35]3 years ago

4 0

To the nearest whole: 4
to the nearest hundredth: 4.2
actual answer: 4.5

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Determine the value of x ? i’m so bad at math. sorry

sergij07 [2.7K]

Answer:

x = 50

Step-by-step explanation:

The legs are perpendicular and so the triangle is a right triangle.

Using the Pythagorean Theorem, we get

48^2 + 14^2 = x^2 = 2304 + 196 = 2500. Then x is the positive square root of 2500, which is 50.

x = 50

3 0

4 years ago

I will give brainly for best answer plzzz help

aivan3 [116]

A.TRUE B.FALSE c.TRUE

4 0

3 years ago

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3x - x + 3 + x - 5 - x = x + 10

egoroff_w [7]

Answer:

x=12

Step-by-step explanation:

Let's solve your equation step-by-step.

3x−x+3+x−5−x=x+10

Step 1: Simplify both sides of the equation.

3x−x+3+x−5−x=x+10

3x+−x+3+x+−5+−x=x+10

(3x+−x+x+−x)+(3+−5)=x+10(Combine Like Terms)

2x+−2=x+10

2x−2=x+10

Step 2: Subtract x from both sides.

2x−2−x=x+10−x

x−2=10

Step 3: Add 2 to both sides.

x−2+2=10+2

x=12

4 0

4 years ago

Read 2 more answers

HELP- Picture Included

emmainna [20.7K]

1000 mg = 1 g
the prefix "milli" means "thousandth", which is why there are 1000 mg in one gram

Use that equation above as the conversion factor
3500 mg = (3500 mg)*(1 g/1000 mg) = (3500/1000) g = 3.5 g

So in short,
3500 mg = 3.5 g

Answer: 3.5

5 0

4 years ago

An aquarium with a square base has no top. There is a metal frame. Glass costs 8 dollars/m^2 and the frame costs 7 dollars/m. Th

Irina-Kira [14]

Given that the volume of the aquarium is 20m^3.

Volume = Area of Base x height

Area of Base = Volume / height = 20/h

Given that the aquarium has a square base.

Area of square = l^2

Thus, the length of the base of the aquarium is $\sqrt{area \ of \ base} = \sqrt{ \frac{20}{h} }$

The frame is to cover 8 sides with the length equal to the length of the base and 4 sides with the length of the height.

Thus, the total perimeter of the frame is given by $8\sqrt{\frac{20}{h}}+4h= \sqrt{64\left(\frac{20}{h}\right)}+4h = \sqrt{\frac{1,280}{h}}+4h$

Area of the four side faces of the aquarium is 4 times the length of the base times the height = $4\times\sqrt{ \frac{20}{h} }\times h=\sqrt{16\left(\frac{20}{h}\right)h^2}=\sqrt{320h}$

Total area to be covered by grass is the base and the four side faces and is given by $\frac{20}{h}+\sqrt{320h}$

Cost of the entire metal frame = $7\left(\sqrt{\frac{1,280}{h}}+4h\right)= \sqrt{49\left(\frac{1,280}{h}\right)}+7(4h) = \sqrt{\frac{62,720}{h}}+28h$

Cost of the entire grass = $8\left(\frac{20}{h}+\sqrt{320h}\right)=\frac{160}{h}+\sqrt{64(320h)}=\frac{160}{h}+\sqrt{20,480h$

Therefore, total cost in terms of the height, h, is given by

$C=\sqrt{\frac{62,720}{h}}+28h+\frac{160}{h}+\sqrt{20,480h$

3 0

4 years ago