This seems to be an incomplete question. I think you want to know the amount of sugar at which both company will charge the same. Based on this idea, i am answering the question.
Let us assume the quantity of sugar = x
Then
For company A, charge = 7500 + 125.25x
For company B, charge = 5995 + 200.50x
Now
7500 + 125.25x = 5995 + 200.50x
7500 - 5995 = 200.50x - 125.25x
1505 = 75.25x
x = 20
From the above deduction it can be concluded that the quantity of sugar at which the prices of both the companies will be the same is 20 ton.
Answer:
x = -5/2
Step-by-step explanation:
3 ^ ( 4x-5) = (1/27) ^( 2x+10)
Rewriting 1/27 as 3^-3
3 ^ ( 4x-5) = (3^-3) ^( 2x+10)
We know that a^b^x = a^(b*c)
3 ^ ( 4x-5) = (3) ^(-3*( 2x+10))
3 ^ ( 4x-5) = (3) ^( -6x-30)
The bases are the same so the exponents are the same
4x-5 = -6x-30
Add 6x to each side
10x -5 = -30
Add 5 to each side
10x -5+5 = -30+5
10x = -25
Divide each side by 10
10x/10 = -25/10
x = -5/2
Combine the fractions by finding a common denominator.
1/25 or 0.04
Answer:
B. x=7
Step-by-step explanation:
(2x+5) = (x+12)
2x = x+7
x=7