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2 years ago

256899 in extended form

Mathematics

1 answer:

Daniel [21]2 years ago

6 0

200000 + 50000 + 6000 + 800 + 90 + 9

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Help!!

yKpoI14uk [10]

Answer:

well....

Step-by-step explanation:

trow the apple

7 0

2 years ago

A rectangular prism had a volume of 252 cubic centimeters. The length of the prism is 14 centimeters and the width of the prism

mojhsa [17]

<h2>Answer:</h2>

A prism is a solid object having two identical bases, hence the same cross section along the length. Prism are called after the name of their base. A rectangular prism is a solid whose base is a rectangle. Multiplying the three dimensions of a rectangular prism: length, width and height, gives us the volume of a prism:

$V=L\times W\times H$

FOR THE ORIGINAL PRISM WE HAVE THE FOLLOWING DIMENSIONS:

$L=14cm \\ \\ W=6cm \\ \\ H=3cm$

In fact, the volume is $252cm^3$ because:

$V=14\times 6\times 3 \therefore V=252cm^3$

Now the height of the prism was changed from 3 centimeters to 6 centimeters to create a new rectangular prism, therefore:

FOR THE NEW PRISM WE HAVE THE FOLLOWING DIMENSIONS:

$L=14cm \\ \\ W=6cm \\ \\ H=6cm$

So the new volume is:

$V=14\times 6\times 6 \therefore V=504cm^3$

<h3><em>What do we know about the volume of the new prism?</em></h3>

<em>Well, the volume has increased from </em> $252cm^3 \ to \ 504cm^3$ <em>and since</em> $504=2\times 252$ <em>we can say that the new volume is two times the original volume.</em>

8 0

2 years ago

Solve the equation by completing the square.Round to the nearest hundredth if necessary. X^2–x–7=0

lesya [120]

NOTE: $\left(x-\dfrac{1}{2}\right)^2=x^2-x+\dfrac{1}{4}$

$x^2-x-7=0 \\ \\ \underbrace{x^2-x+\frac{1}{4}}_{\left(x-\frac{1}{2}\right)^2}-7\dfrac{1}{4}=0 \\ \\ \\ \left(x-\frac{1}{2}\right)^2=7\frac{1}{4}=\frac{29}{4} \qquad /\sqrt{}\\ \\ \left|x-\frac{1}{2}\right|=\dfrac{\sqrt{29}}{2} \\ \\ x_1=\dfrac{1}{2}-\dfrac{\sqrt{29}}{2} \approx -2.19 \\ \\ x_2=\dfrac{1}{2}+\dfrac{\sqrt{29}}{2} \approx 3.19$

ANSWER: c)

5 0

2 years ago

the conference room of a hotel measures 40 ft by 50 ft has a 12-foot ceiling what is the area of the walls

Softa [21]

Answer:

The area of the walls is $2,160\ ft^{2}$

Step-by-step explanation:

we know that

The area of the walls is equal to the perimeter of the conference room multiplied by the height of the ceiling

$A=2[40+50](12)=2,160\ ft^{2}$

5 0

2 years ago

. Which of the equations below has a solution of 3? A 2 r= 6 B 6 = 2 rC 2r = 6

yaroslaw [1]

Answer:

They all have a solution of 3.

Step-by-step explanation:

Each of the equations represented are basically the same thing, therefore have the same answer.

A) 2r = 6 - You would divide 6 by 2 and you would get 3.

B) 6 = 2r - You would still divide 6 by 2, which equals 3.

C) 2r = 6 - Then again you would divide 6 by 2 to get 3.

- <em>I hope this helps :)</em>

6 0

2 years ago