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nlexa [21]
4 years ago
13

The sum of two numbers is 20. Their difference is 14. Find the numbers.

Mathematics
2 answers:
Mila [183]4 years ago
5 0
3 and 17
17-3=14

hope that helps
Maksim231197 [3]4 years ago
5 0
X-Y = 14, X+Y = 20, then x=14+Y. Replace x so (14+Y) + Y =20 so 2Y = 6, Y=3 and x=17
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Please help<br> I’ll give brain-lest
MrRissso [65]

Answer:

TU = 29

Step-by-step explanation:

TU + UV = TV , substitute values

9x + 2 + 5 = 14x - 8 , that is

9x + 7 = 14x - 8 ( subtract 14x from both sides )

- 5x + 7 = - 8 ( subtract 7 from both sides )

- 5x = - 15 ( divide both sides by - 5 )

x = 3

Then

TU = 9x + 2 = 9(3) + 2 = 27 + 2 = 29

3 0
3 years ago
The aswers are 90 180 or 270
dimaraw [331]

Answer:

90? May be wrong though!

Step-by-step explanation:

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3 years ago
What is 1 and 1/4, 3/2, 1 and 6/8. 1 whole from least to greatest?
Anastaziya [24]
Answer: 1, 1&1/4, 3/2, 1&6/8
3 0
3 years ago
Suppose we have a binomial experiment with n= 40 trials and a probability of success p= 0.50.Is it appropriate to use a normal a
exis [7]

Answer:

We can approximate to normal.

The parameters of the approximate normal distribution are:

\mu=np=40*0.5=20\\\\ \sigma=\sqrt{npq} =\sqrt{40*0.5*0.5} =\sqrt{10} =3.16

P_B(r>23)\approx 0.314

It is not unusual to have 23 or more successes. The probabiltity of this event happening is 13.4%.

Step-by-step explanation:

To approximate the binomial distribution to a normal distribution, we can calculate n*p and n*q and if both are bigger than 5 we can do the approximation.

n*p=n*q=0.5*40=20

We can approximate to normal.

The parameters of the approximate normal distribution are:

\mu=np=40*0.5=20\\\\ \sigma=\sqrt{npq} =\sqrt{40*0.5*0.5} =\sqrt{10} =3.16

The continuity correction factor is used because the binomial is a discrete function and the normal a continous function.

The probability of 23 successes must be expressed in the normal distribution as:

P_B(r>23)=P_N(r>23+0.5)=P_N(r>23.5)\\\\z=(23.5-20)/3.16=1.1076\\\\P(r>23.5)=P(z>1.1076)=0.134\\\\P_B(r>23)\approx 0.314

It is not unusual to have 23 or more successes. The probabiltity of this event happening is 13.4%.

3 0
3 years ago
What is the solution to the equation
galben [10]

Answer:B

Step-by-step explanation:

4 0
3 years ago
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