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almond37 [142]
3 years ago
12

WHO RUNS THE FASTEST? HELP

Mathematics
2 answers:
Vlada [557]3 years ago
7 0

Answer:

Jessica runs the fastest

Step-by-step explanation:

If you divide all of the lengths they ran by the time it took them to run in seconds, you find how much feet they run each second and Jessica ran the most feet in the least amount of time which means she runs the fastest.

artcher [175]3 years ago
6 0

Answer:

I think your answer is Frank.

Step-by-step explanation:

Frank runs in miles and miles are bigger than feet.

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Find the area, please help me, having a hard time getting through tonight’s homework. Complex/Compound area. Thanks!
Digiron [165]
Since the bottom shape is a semi-circle, the 3yd is the radius making the triangle's area 7 x 3 / 2 = 10.5

The semi-circle's area is \pi 3^{2} /2 = 14.14

Combined, you get an area of 10.5 + 14.14 = 24.64yd^{2}
7 0
3 years ago
A line passes through (-6,-1) and (3,2).What is the equation of the line?
Lina20 [59]

Answer:

y = (1/3)x + 1

Step-by-step explanation:

You first find the slope:

(2 - (-1))/(3 - (-6)) =

3/9 =

1/3

This means the equation of the line is y = (1/3)x + b, where b is a real number.

Plug in either of the points to find the value of b:

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-1 = -2 +b -->

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This means the equation is y = (1/3)x + 1

3 0
3 years ago
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On a coordinate grid what is the distance from g 2,8 to h 2,5
Anika [276]
(2, 8), (2, 5)

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8 - 5 = 3

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5 0
3 years ago
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What would you do if you saw a to 99 year old women fighting over a 21 year old man
Sophie [7]

Answer:

kick them to the moon. <D

Step-by-step explanation:

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3 0
3 years ago
A ferry will safely accommodate 82 tons of passenger cars. Assume that the meanweight of a passenger car is 2 tons with standard
Shalnov [3]

Answer:

The probability that the maximum safe-weight will be exceeded is <u>0.0455 or 4.55%</u>.

Step-by-step explanation:

Given:

Maximum safe-weight of 37 cars = 82 tons

∴ Maximum safe-weight of 1 car (x) = 82 ÷ 37 = 2.22 tons (Unitary method)

Mean weight of 1 car (μ) = 2 tons

Standard deviation of 37 cars = 0.8 tons

So, standard deviation of 1 car is given as:

\sigma=\frac{0.8}{\sqrt{37}}=0.13

Probability that maximum safe-weight is exceeded, P(x > 2.22) = ?

The sample is normally distributed (Assume)

Now, let us determine the z-score of the mean weight.

The z-score is given as:

z=\frac{x-\mu}{\sigma}\\\\z=\frac{2.22-2}{0.13}\\\\z=\frac{0.22}{0.13}=1.69

Now, finding P(x > 2.22) is same as finding P(z > 1.69).

From the z-score table of normal distribution curve, the value of area under the curve for z < 1.69 is 0.9545.

But we need the area under the curve for z > 1.69.

So, we subtract from the total area. Total area is 1 or 100%.

So, P(z > 1.69) = 1 - P(z < 1.69)

P(z>1.69)=1-0.9545=0.0455\ or\ 4.55\%

Therefore, the probability that the maximum safe-weight will be exceeded is 0.0455 or 4.55%.

8 0
3 years ago
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