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neonofarm [45]
3 years ago
9

2x - 5y + 3z 5x + 9y - 2z

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
7 0

Answer:

3xz5+2x+4y−2z

Step-by-step explanation:

2x−5y+3z5x+9y−2z

=2x+−5y+3xz5+9y+−2z

Combine Like Terms:

=2x+−5y+3xz5+9y+−2z

=(3xz5)+(2x)+(−5y+9y)+(−2z)

=3xz5+2x+4y+−2z

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Tasya [4]

Answer:

We want to find:

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Here we can use Stirling's approximation, which says that for large values of n, we get:

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Then we get.

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} =  \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}

Now we can just simplify this, so we get:

\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\

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\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

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3 years ago
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Step-by-step explanation:

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5 0
3 years ago
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Step-by-step explanation:

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Answer:

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