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2 years ago

What is the domain and range of the relation shown in the table?

Mathematics

1 answer:

Leokris [45]2 years ago

5 0

Answer:

domain: {-12, -8, 0, 1} range: {0, 8, 12}

Step-by-step explanation:

domain are of all the input values shown on the x-axis. The range is the set of possible output shown on the y-axis.

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Frodo and Sam are photographers. They take pictures of seniors for high school yearbooks. They charge a standard fee for taking

liubo4ka [24]

(0,15)(1,19)
slope = (19 - 15) / (1 - 0) = 4

y = mx + b
slope(m) = 4
(0,15)...x = 0 and y = 15
sub
15 = 4(0) + b
15 = b

y = 4x + 15....so ur rule is : F(s) = 4s + 15

7 0

3 years ago

If a polyhedron has 5 faces and 7 vertices, then it must have how many edges? Please show step-by-step work

Juli2301 [7.4K]

Answer:

10 edges

Step-by-step explanation:

we know that

The Euler's formula state that: In a polyhedron, the number of vertices, minus the number of edges, plus the number of faces, is equal to two

$V - E + F = 2$

in this problem we have

$V=7\\E=?\\F=5$

substitute the given values

$7 - E + 5 = 2$

solve for E

Combine like terms in the left side

$12 - E = 2$

subtract 12 both sides

$- E = -10$

Multiply by -1 both sides

$E =10$

8 0

2 years ago

Which could be the first step in simplifying this expression? Check all that apply. (x cubed x Superscript negative 6 Baseline)

PtichkaEL [24]

Answer:

$(x^{-3} )^{2}$

$x^6 x^{-12}$

Step-by-step explanation:

$(x^{3} x^{-6} )^{2}$ is the expression given to be solved.

First of all let us have a look at 3 formulas:

$1.\ p^a \times p^b = p^{(a+b)}\\2.\ (p^a \times q^b)^c = (p^{a})^c \times (q^{b})^c\\3.\ (p^a)^b = p^{a\times b}$

Both the formula can be applied to the expression( $(x^{3} x^{-6} )^{2}$ ) during the first step while solving it.

Applying formula (1):

$(x^{3} x^{-6} )^{2}$

Comparing the terms of $(x^{3} x^{-6} )$ with $p^a \times p^b$

$p=x, a =3, b=-6$

$\Rightarrow x^{3+(-6)}\\\Rightarrow x^{3-6}\\\Rightarrow x^{-3}$

So, $(x^{3} x^{-6} )^{2}$ is reduced to $(x^{-3} )^{2}$

Applying formula (2):

Comparing the terms of $(x^{3} x^{-6} )^{2}$ with $(p^a \times q^b)^c$

$p=q=x, a =3, b=-6, c=2$

$\Rightarrow (x^{3})^2\times (x^{-6})^2\\\text{Applying Formula (3)}\\x^6 x^{-12}$

So, $(x^{3} x^{-6} )^{2}$ is reduced to $x^6 x^{-12}$ .

So, the answers can be:

$(x^{-3} )^{2}$

$x^6 x^{-12}$

8 0

2 years ago

A cylinder is sliced by a plane that is not parallel to the base

pickupchik [31]

I guess you are asking what is the shape of the cross section.

It will be an ellipse.

4 0

3 years ago

Which expression is equivalent to

lisabon 2012 [21]

Answer:

i think the answer is, A...

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2 years ago