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3 years ago

How do i even solve this?? i’m super confused anything would help. ty.

Mathematics

1 answer:

alukav5142 [94]3 years ago

5 0

Answer:

${b}^{4} + 1$

Your teacher messed up the question so just put the top right answer and ask your teacher if they did accidently miss-type.

Step-by-step explanation:

The first thing to do in this equation is look at the exponents. When multiplying a variable (or any number equal to itself with the same exponent) you only have to add the exponent. So for a, you would add the exponents to get 0, so a to the power of 0 is 1, because any number to the power of 0 is 1. For b, we would add the 3 and 1. (When no exponenet is present in a number then it is 1, so for this I added 3 and 1). So it would be 4. The correct answer is

${b}^{4} + 1$

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What is the equation of the circle with center (0, 0) that passes through the point (–4, –6)?

Vadim26 [7]

If the center is in point P(a,b) and has a radius r then circle equation is:

(x-a)²+(y-b)²=r².

In your task we've got P(0,0) so the circle equation is x²+y²=r².

We have to find r. Radius start at (0,0) and end at (-4,-6) therefore

r=√((-4)²+(-6)²) and

r²=(-4)²+(-6)²=16+36=52.

So answer is x²+y²=52.

4 0

3 years ago

Assume that a cross is made between a heterozygous tall pea plant and a homozygous short pea plant. Fifty offspring are produced

Butoxors [25]

Answer:

1) $\chi^2 = \frac{(30-25)^2}{25} +\frac{(20-25)^2}{25} =1 +1 =2$

2) $df = c-1 = 2-1$

Where c represent the number of categories c=2

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Tall =30 , Short =20

We need to conduct a chi square test in order to check the following hypothesis:

H0: The deviations from a 1:1 ratio (25 tall and 25 short) are due to chance.

H1: The deviations from a 1:1 ratio (25 tall and 25 short) are NOT due to chance.

Part 1

So then we know that the expected values would be 25 for each case

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

And if we replace we got:

$\chi^2 = \frac{(30-25)^2}{25} +\frac{(20-25)^2}{25} =1 +1 =2$

Part 2

For this case the degreed of freedom are given by:

$df = c-1 = 2-1$

Where c represent the number of categories c=2

And we can calculate the p value given by:

$p_v = P(\chi^2_{1} >2)=0.157$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(2,1,TRUE)"

7 0

3 years ago

jar contains 51 coins which are either quarters or nickels. total value of jar is 5.15. how many of each type of coin do they ha

docker41 [41]

I believe there are 20 quarters and 3 nickels.....

Total value of the jar is $5.15.....

Quarters are worth 25 cents
And nickels are worth 5 cents.

First you know that there are 4 quarters in a dollar.
You have 5 dollars so you do 4 x 5 = 20

So five dollars ($5.00) is 20 quarters.
And you still have 15 cents left.

Because quarters are 25 cents the rest are nickels.

Nickels are worth 5 cents so you'd do 5 x 3 = 15.

15 cents!

Add all this together and get $5.15.

So your answer is

There are 20 quarters and 3 nickels in the jar.

8 0

3 years ago

Please answer I will make you Brainliest if it's right How do I do this step by step??

Sav [38]

Answer:

$\sqrt{2 \times 2 \times 2 \times 3 } = \sqrt{24} = \sqrt{4 \times 6} = 2 \sqrt{6}$