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Allisa [31]
2 years ago
10

How do i even solve this?? i’m super confused anything would help. ty.

Mathematics
1 answer:
alukav5142 [94]2 years ago
5 0

Answer:

{b}^{4}  + 1

Your teacher messed up the question so just put the top right answer and ask your teacher if they did accidently miss-type.

Step-by-step explanation:

The first thing to do in this equation is look at the exponents. When multiplying a variable (or any number equal to itself with the same exponent) you only have to add the exponent. So for a, you would add the exponents to get 0, so a to the power of 0 is 1, because any number to the power of 0 is 1. For b, we would add the 3 and 1. (When no exponenet is present in a number then it is 1, so for this I added 3 and 1). So it would be 4. The correct answer is

{b}^{4}  + 1

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What is the arc length of AB?
Airida [17]

Answer:

Length of the given arc AB = 7.33 in.

Step-by-step explanation:

Formula to calculate the arc length is,

Arc length = \frac{\theta}{360}(2\pi r)

Where θ is the measure of central angle subtended by the arc.

And 'r' = radius of the circle

By substituting the values given in the formula,

Length of arc AB = \frac{60}{360}\times (2\pi )\times (7)

                            = \frac{14\pi}{6}

                            = \frac{7\pi}{3}

                            = 7.33 in.

Therefore, length of the given arc AB = 7.33 in.

4 0
3 years ago
PLLLLEEEEEEAAASSSSSSSSEEEE
mrs_skeptik [129]

Given:

Line a passes through (2, 10) and (4, 13).

Line b passes through (4, 9) and (6, 12).

Line c passes through (2, 10) and (4, 9).

To find:

Which of the lines, if any are perpendicular.

Solution:

If a line passes through two points, then the slope of line is

m=\dfrac{y_2-y_1}{x_2-x_1}

Line a passes through (2, 10) and (4, 13).  So, slope of this line is

m_a=\dfrac{13-10}{4-2}=\dfrac{3}{2}

Line b passes through (4, 9) and (6, 12).  So, slope of this line is

m_b=\dfrac{12-9}{6-4}=\dfrac{3}{2}

Line c passes through (2, 10) and (4,9).  So, slope of this line is

m_c=\dfrac{9-10}{4-2}=\dfrac{-1}{2}

Product of slopes of to perpendicular lines is -1.

m_a\cdot m_b=\dfrac{3}{2}\times \dfrac{3}{2}=\dfrac{9}{4}\neq -1

m_b\cdot m_c=\dfrac{3}{2}\times \dfrac{-1}{2}=\dfrac{-3}{4}\neq -1

m_a\cdot m_c=\dfrac{3}{2}\times \dfrac{-1}{2}=\dfrac{-3}{4}\neq -1

Therefore, any of these lines are not perpendicular to each other.

8 0
3 years ago
finding the distance from (–6, 2) to the origin. Use (0, 0) as (x1, y1). d = StartRoot (x 2 minus x 1) squared + (y 2 minus y 1)
Naddik [55]

Answer:

2√10

Step-by-step explanation:

Given the coordinates (-6, 2) and (0,0)

We are to find the distance between the coordinates. Using the distance formula;

d = √(x2-x1)²+(y2-y1)²

d = √(0-2)²+(0+6)²

d = √(-2)²+(6)²

d = √4+36

d = √40

d = √4*10

d = 2√10

Hence the required distance is 2√10

4 0
3 years ago
Find the equation of the line
Fed [463]

Answer:

6,0 10,4

Step-by-step explanation:

find the y Axis and then the x Axis

5 0
3 years ago
Line V has a slope of 8/9. Line w is perpendicular to V. What is the slope of line W?
Alex787 [66]

Answer:

W = -9/8

Step-by-step explanation:

for two perpendicular lines

W*V = -1

W = 9/8*(-1)

W= -9/8

6 0
3 years ago
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