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irga5000 [103]
3 years ago
8

I need help with this

Mathematics
1 answer:
laiz [17]3 years ago
5 0

Answer:

y = (3/2)x -3

Step-by-step explanation:

y = mx + b, where m = slope and b = y-intercept

The slope is 3/2 and the y-intercept is (0, -3)

y = (3/2)x -3

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Find the holes<br> <img src="https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7Bx%2B3%7D%7B%28x%2B1%29%28x-2%29%7D" id="TexFormula1" t
olga55 [171]

Answer:

<h2>           x=-1 and x=2</h2>

Step-by-step explanation:

The "holes" are the x-es where function doesn't exist.

one must not divide by 0, so given function doesn't exis if the denominator is equal 0

The product {(x+1)×(x-2)} is equal 0 if any of factors  {(x+1),(x-2)} is 0, so

x + 1 = 0    or    x - 2 = 0

x = - 1      or    x = 2

8 0
3 years ago
The numbers $1,$ $2,$ $\dots,$ $10$ are to be entered into the 10 boxes shown below, so that each number is used exactly once: \
Agata [3.3K]

Answer:

Maximum =  756

Minimum =  600

Step-by-step explanation:

A square is a shape that has the large areas of a defined perimeter out of available rectangles. It implies they want the two parentheses to be as similar in value. as a result, to establish the maximum value of P.

And to establish the minimum value, to have the greatest difference for them. 1 + 2 + 3 ... +10=55, which wasn't even but which can be split as similarly as possible into 27 and 28 which have a product of 756. In this question it can be done in a variety of ways, one of which is:

(1 + 3 + 5 + 8 + 10) ×  (2 + 4 + 6 + 7 + 9) = 756

At the very least, the biggest difference can be created if one term is made of the smallest numbers, while the other full of the highest, or:

(1 + 2 + 3 + 4 + 5) × (6 + 7 + 8 + 9 + 10)=600

8 0
3 years ago
Find dy/dx given that y = sin x / 1 + cos x​
kobusy [5.1K]

Answer:

\frac{1}{1 +  \cos(x) }

Step-by-step explanation:

y =  \frac{ \sin(x) }{1 +  \cos(x) }

<u>differentiating numerator wrt x :-</u>

(sinx)' = cos x

<u>differentiating denominator wrt x :- </u>

(1 + cos x)' = (cosx)' = - sinx

  • Let's say the denominator was "v" and the numerator was "u"

(\frac{u}{v}  )'  =  \frac{v. \: (u)'  - u.(v)' }{ {v}^{2} }

here,

  • since u is the numerator u= sinx and u = cos x
  • v(denominator) = 1 + cos x; v' = - sinx

=  \frac{((1 +  \cos \: x) \cos \: x )- (\sin \: x. ( -  \sin \: x)  ) }{( {1 +  \cos(x)) }^{2} }

=  \frac{ \cos(x)  +  \cos {}^{2} (x)  +   \sin {}^{2} (x) }{(1 +  \cos \: x) {}^{2}  }

since cos²x + sin²x = 1

=  \frac{ \cos \: x + 1}{(1 +  \cos \: x) {}^{2}  }

diving numerator and denominator by 1 + cos x

=  \frac{1}{1 +  \cos(x) }

6 0
3 years ago
Does anyone know how to do geometry
olchik [2.2K]
The answer to our question is yes
7 0
3 years ago
What is the simple subject of I could feel the rain on my left shoulder.
ahrayia [7]
This a dang easy question. Ask yourself,what is the sentence about?



7 0
3 years ago
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