Answer:
50.27in
Step-by-step explanation:
Given data
Diameter of small tire= 13in
Radius= 13/2= 6.5in
Circumference= 2πr
C= 2*3.142*6.5
C= 40.85 in
Diameter of Big tire= 29in
Radius= 29/2= 14.5in
Circumference= 2πr
C= 2*3.142*14.5
C= 91.118in
Hence the difference in distance between the two tires after on revolution is
=91.118-40.85
=50.27in
The answer for y is positive
2 to the average 5 and times the inequality of 16-inch
true a segment has a finite length and to determent endpoints
