Question

Multiply (6z^2-4z+1)(8-3z).

Answer 1

So for this, our equation can be rewritten as (thanks to distributive property): $(6z^2*8)+(6z^2*(-3z))+(-4z*8)+(-4z*(-3z))+(1*8)+(1*(-3z))$

Firstly, multiply everything: $48z^2-18z^3-32z+12z^2+8+-3z$

Next, combine like terms and your answer will be: $-18z^3+60z^2-35z+8$