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3 years ago

What is the product of the expression (r - 7) (x-3)?

Mathematics

2 answers:

dem82 [27]3 years ago

8 0

Answer:

rx-3r-7x+21

Step-by-step explanation:

Since you don't know what r or x stand for, you need to distribute.

First, you would do r(x-3)-7(x-3)

Then, you would distribute again to make it rx-3r-7(x-3)

Last, you would distribute AGAIN to make it rx-3r-7x+21

The 21 comes from 7·x and 7·3

o-na [289]3 years ago

5 0

Answer:

the ration is 3:7r

Step-by-step explanation:

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You start off by multiplying the second bracket by -1 to get rid of the bracket.
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3 years ago

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$\frac{\sin B}{b}=\frac{\sin A}{a} \\ \\ \sin B=\frac{b \sin A}{a} \\ \\ \sin B=\frac{13 \sin 29^{\circ}}{7.2} \\ \\ \boxed{m\angle B =\arcsin \left(\frac{65\sin 29^{\circ}{36} \right), 180^{\circ}-\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right)}$

Considering the diagram. $\angle B$ is shown to be acute, so $\boxed{m\angle B=\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right)}$ .

Angles in a triangle add to 180°, so $m\angle C= 151^{\circ}-\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right)$ .

Using the law of cosines,

$AB=\sqrt{13^2 + 7.2^2-2(13)(7.2)\cos \left(\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right) \right)} \\ \\ \boxed{AB=\sqrt{220.84-187.2\cos \left(\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right) \right)}}$

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