We have been given that a sphere and a cylinder have the same radius and height. The volume of the cylinder is 21 meters cubed. We are asked to find the volume of the sphere.
We know that height of sphere is equal to its radius. This means that 
.
Using , we will get:
Upon comparing volume of sphere and volume of cylinder, we can see that volume of sphere is 
times volume of cylinder.
Therefore, the volume of the sphere would be 28 cubic meters.
The reciprocal is just the fraction flipped over. 7/6 flipped is 6/7.
Tn=n²+3
from 4 to 7....the difference is 3, then from 7 to 12 the difference is 5 and from 12 to 19 the difference is 7
therefore we constantly add 2 to the difference
-4(x-1)=-3x+13-9-x
-4x+4=-3x+4-x
-4x+4=-4x+4
-4x=-4x
0=0
Answer:
Approximately 6.4
Step-by-step explanation:
We can use the pythagorean thereom here, that tells us (a^2)+(b^2)=c^2. C is the hypotenuse, the side opposite from the right angle, while a and b are the other sides. We can insert 5 and 4 as a and b, and solve for c
:(5^2)+(4^2)=c^2
:25+16=c^2
:41=c^2
:sqrt(41)=6.4=c (We square rooted both sides. 6.4 is only rounded to the nearest hundredths place.) Hope this helps!
