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pishuonlain [190]
3 years ago
12

Janine’s credit card wasn’t stolen, and the thief charged a $44 meal before she reported it stolen. how much of this is Janine r

esponsible for paying ?
Mathematics
1 answer:
nirvana33 [79]3 years ago
4 0
So the answer Janine responded for paying back 44 I am not too sure
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Point M is the midpoint of AB. The coordinates of point A are (-8, 3) and the coordinates of M are (-2, 1). What are the coordin
ch4aika [34]

Answer:

the coordinates of point B are (-5, 2)

Step-by-step explanation:

1. use midpoint formula to find the midpoint (equation attached below)

2. plug in the numbers

(\frac{-8+(-2)}{2},\frac{3+1}{2})

3. solve

(\frac{-8-2)}{2},\frac{3+1}{2})

(\frac{-10}{2},\frac{4}{2})

(-5,2})

4 0
3 years ago
Studies show that a typical giant hummingbird can flap its wings once in 0.08 of a second.
Licemer1 [7]

Answer:

a. 90

b. 360

Step-by-step explanation:

The time taken by humming bird to flap its wings= 0.08 sec

by flying 7.2 seconds a typical giant hummingbird flap its wings \frac{7.2}{0.08} times

= 90 times

Since, A ruby-throated hummingbird can flap its wings 4 times faster than a giant hummingbird, it will flap its wings in every 0.02 sec

so in 7.2 seconds it will flap \frac{7.2}{0.02} times = 360 times

4 0
3 years ago
Two competitive neighbours build rectangular pools that cover the same area but are different shapes. Pool A has a width of (x +
GenaCL600 [577]

<u>Answer: </u>

a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

b) Area of pool A is equal to area of pool B equal to 24.44 meters.

<u> Solution: </u>

Let’s first calculate area of pool A .

Given that width of the pool A = (x+3)  

Length of the pool A is 3 meter longer than its width.

So length of pool A = (x+3) + 3 =(x + 6)

Area of rectangle = length x width

So area of pool A =(x+6) (x+3)        ------(1)

Let’s calculate area of pool B

Given that length of pool B is double of width of pool A.

So length of pool B = 2(x+3) =(2x + 6) m

Width of pool B is 4 meter shorter than its length,

So width of pool B = (2x +6 ) – 4 = 2x + 2

Area of rectangle = length x width

So area of pool B =(2x+6)(2x+2)        ------(2)

Since area of pool A is equal to area of pool B, so from equation (1) and (2)

(x+6) (x+3) =(2x+6) (2x+2)    

On solving above equation for x    

(x+6) (x+3) =2(x+3) (2x+2)  

x+6 = 4x + 4    

x-4x = 4 – 6

x = \frac{2}{3}

Dimension of pool A

Length = x+6 = (\frac{2}{3}) +6 = 6.667m

Width = x +3 = (\frac{2}{3}) +3 = 3.667m

Dimension of pool B

Length = 2x +6 = 2(\frac{2}{3}) + 6 = \frac{22}{3} = 7.333m

Width = 2x + 2 = 2(\frac{2}{3}) + 2 = \frac{10}{3} = 3.333m

Verifying the area:

Area of pool A = (\frac{20}{3}) x (\frac{11}{3}) = \frac{220}{9} = 24.44 meter

Area of pool B = (\frac{22}{3}) x (\frac{10}{3}) = \frac{220}{9} = 24.44 meter

Summarizing the results:

(a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

(b)Area of pool A is equal to Area of pool B equal to 24.44 meters.

5 0
4 years ago
Evaluate 29 • 1 + 2(20 ÷ 4 – 5)
Leno4ka [110]

29..................................

8 0
4 years ago
Read 2 more answers
What is the solution to the equation below? Enter the answer in the format p=#, keep your answer as a fraction if necessary. -2/
Scorpion4ik [409]

Let's solve your equation step-by-step.

-2/3p+ 1/6= 7/10

Answer:

p= -4/5

6 0
3 years ago
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