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3 years ago

Yesterdays low temperature was -2.5°C today low temperature is five times as lone as yesterday’s low temperature

Mathematics

1 answer:

zimovet [89]3 years ago

6 0

Answer:

-12.5°C

Step-by-step explanation:

To solve this problem you would multiply -2.5 by 5.

-2.5 * 5 = -12.5

Today's low temperature is -12.5°C.

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find two consecutive even numbers such that the sum of 3 times the smaller and 5 times the larger is 106

VARVARA [1.3K]

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Read 2 more answers

Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.

suter [353]

Answer:

$\theta = 30^\circ, 330^\circ$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

Step-by-step explanation:

Given [Missing from the question]

Equation:

$cos\theta = \frac{\sqrt 3}{2}$

Interval:

$0 \le \theta \le 360$

$0 \le \theta \le 2\pi$

Required

Determine the values of $\theta$

The given expression:

$cos\theta = \frac{\sqrt 3}{2}$

... shows that the value of $\theta$ is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

$cos\theta = \frac{\sqrt 3}{2}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{\sqrt 3}{2})$

$\theta = 30$ --- In the first quadrant

In the fourth quadrant, the value is:

$\theta = 360 -30$

$\theta = 330$

So, the values of $\theta$ in degrees are:

$\theta = 30^\circ, 330^\circ$

Convert to radians (Multiply both angles by $\pi/180$ )

So, we have:

$\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}$

$\theta = \frac{\pi}{6}, \frac{33 * \pi}{18}$

$\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

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3 years ago

The set of all numbers less than or equal to -1

kolbaska11 [484]

Answer:

-10,-100,-8,-7,-2,-4,-5,-20,-6,-3,-7

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3 years ago