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Katyanochek1 [597]
3 years ago
8

Yesterdays low temperature was -2.5°C today low temperature is five times as lone as yesterday’s low temperature

Mathematics
1 answer:
zimovet [89]3 years ago
6 0

Answer:

-12.5°C

Step-by-step explanation:

To solve this problem you would multiply -2.5 by 5.

-2.5 * 5 = -12.5

Today's low temperature is -12.5°C.

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The limit of \lim_{x \to -3}\sqrt{ x^2-8} as x approaches negative 3 is 1

<h3>Limit of a function </h3>

The limit of the function given in question can also be written as:

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To determine the required limit, we will simply substitute the value of x into the function as shown:

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Hence the limit of \lim_{x \to -3}\sqrt{ x^2-8} as x approaches negative 3 is 1

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