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vladimir2022 [97]
3 years ago
15

Membrane-bound organelles are not found in the cells of A) bacteria. B) fungi. C) plants. Eliminate D) protists.

Computers and Technology
2 answers:
Luden [163]3 years ago
8 0
Yes bacteria has free floating organelles
77julia77 [94]3 years ago
7 0
The answer is A. Bacteria leave a thanks if i am correct please.
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Entering the formula =SUM(C5:C18) in cell C19 will result in which of the following?
frozen [14]
Well the result shown in C19 will show the sum of all cells from C5 to C18:
ie: C5 + C6+ C7+ C8+ C9+ C10+ C11+ C12+ C13+ C14+ C15+ C16+ C17+ C18

:)
3 0
3 years ago
Henry has created a software product that manages a database of company clients. He wants to install the software on a client's
UkoKoshka [18]

Answer:

The answer is " Run the software on the original web browser practically".

Explanation:

The Virtual servers enable you to run programming not programmed to the devices. Let's all presume which Henry's software will operate on computers but not on the mac. Since Mac is unable to run this software, it can practically install Linux on MC and install this.

  • The several common software applications such as parallels, VMware, and Virtual machines could be practically used during mac to install windows.
  • Its platform operating system from a macOS software perspective is a true physical computer with almost everything set.
5 0
2 years ago
A 4-bit left shift register is initially in the 0000 state, with all the flip flops storing 0s. A group of bits 1011 is serially
frutty [35]

Answer:

0010

Explanation:

Serially left shifted means that the left most bit will enter the register first. The left most bit already stored in the register will move out of the sequence. The "bold" bits mentioned below highlight these left most bits:

Initial State of the Register:

0000

Group of bits entering:

1011

<u>First Clock Cycle:</u>

0000 <em>(This bold bit will move out)</em>

1011 <em>(This bold bit will move in from right side, shifting the whole sequence one place to the left).</em>

The resulting Sequence:

0001

<u>Second Clock Cycle:</u>

0001 <em>(This bold bit will move out)</em>

1011 <em>(This bold bit will move in from right side, shifting the whole sequence one place to the left).</em>

The resulting Sequence:

0010 <em>(Final Answer)</em>

6 0
3 years ago
Develop a C program that calculates the final score and the average score for a student from his/her (1)class participation, (2)
Ghella [55]

Answer:

#include <iomanip>

#include<iostream>

using namespace std;

int main(){

char name[100];

float classp, test, assgn, exam, prctscore,ave;

cout<<"Student Name: ";

cin.getline(name,100);

cout<<"Class Participation: "; cin>>classp;

while(classp <0 || classp > 100){  cout<<"Class Participation: "; cin>>classp; }

cout<<"Test: "; cin>>test;

while(test <0 || test > 100){  cout<<"Test: "; cin>>test; }

cout<<"Assignment: "; cin>>assgn;

while(assgn <0 || assgn > 100){  cout<<"Assignment: "; cin>>assgn; }

cout<<"Examination: "; cin>>exam;

while(exam <0 || exam > 100){  cout<<"Examination: "; cin>>exam; }

cout<<"Practice Score: "; cin>>prctscore;

while(prctscore <0 || prctscore > 100){  cout<<"Practice Score: "; cin>>prctscore; }

ave = (int)(classp + test + assgn + exam + prctscore)/5;

cout <<setprecision(1)<<fixed<<"The average score is "<<ave;  

return 0;}

Explanation:

The required parameters such as cin, cout, etc. implies that the program is to be written in C++ (not C).

So, I answered the program using C++.

Line by line explanation is as follows;

This declares name as character of maximum size of 100 characters

char name[100];

This declares the grading items as float

float classp, test, assgn, exam, prctscore,ave;

This prompts the user for student name

cout<<"Student Name: ";

This gets the student name using getline

cin.getline(name,100);

This prompts the user for class participation. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

<em> cout<<"Class Participation: "; cin>>classp; </em>

<em> while(classp <0 || classp > 100){  cout<<"Class Participation: "; cin>>classp; } </em>

This prompts the user for test. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

<em> cout<<"Test: "; cin>>test; </em>

<em> while(test <0 || test > 100){  cout<<"Test: "; cin>>test; } </em>

This prompts the user for assignment. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

<em> cout<<"Assignment: "; cin>>assgn; </em>

<em> while(assgn <0 || assgn > 100){  cout<<"Assignment: "; cin>>assgn; } </em>

This prompts the user for examination. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

<em> cout<<"Examination: "; cin>>exam; </em>

<em> while(exam <0 || exam > 100){  cout<<"Examination: "; cin>>exam; } </em>

This prompts the user for practice score. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

<em> cout<<"Practice Score: "; cin>>prctscore; </em>

<em> while(prctscore <0 || prctscore > 100){  cout<<"Practice Score: "; cin>>prctscore; } </em>

This calculates the average of the grading items

ave = (int)(classp + test + assgn + exam + prctscore)/5;

This prints the calculated average

cout <<setprecision(1)<<fixed<<"The average score is "<<ave;  

8 0
3 years ago
Who likes sandshrew ​
zvonat [6]

Answer:

sandshrew is a cute character in pokemon

6 0
3 years ago
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