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lora16 [44]
3 years ago
14

If f(x) = -x + 8 and g(x) = x4, what is (gºf)(2)? Enter the correct answer.

Mathematics
1 answer:
quester [9]3 years ago
4 0

Answer:

\large\boxed{(g\circ f)(2)=1296}

Step-by-step explanation:

f(x)=-x+8,\ g(x)=x^4\\\\(g\circ f)(x)=g\bigg(f(x)\bigg)\\\\(g\circ f)(x)=\bigg(-x+8\bigg)^4\\\\(g\circ f)(2)\to\text{put x - 0 to the equation of the function:}\\\\(g\circ f)(2)=(-2+8)^4=(6)^4=1296

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Yasmine made waffles for her family.4/7 of the waffles where blueberry 1/7 of the waffles where chocolate chip . The rest of the
Alexxx [7]

Answer:

2/7 of the waffles did not have blueberries or chocolate chips.

Step-by-step explanation:

So first, it says 4/7 were blueberry, and 1/7 were chocolate chip. When you add them two you get 5/7. The denominator is 7, so subtract 7 from 5 and you get 2, 2/7. 2/7 of the waffles did not have blueberries or chocolate chips.

7 0
3 years ago
1-x-5x=8x-5<br> Show your work
nataly862011 [7]

Answer:

13

Step-by-step explanation:

its 13 calculator

4 0
3 years ago
Read 2 more answers
En las olimpiadas matemáticas,la hora de inicio del evento se expresa en una ecuación simple: 2x+6=x+17 ¿A qué hora empezó el ev
Sergio [31]

Answer:

11 minutos.

Step-by-step explanation:

En las Olimpiadas de Matemáticas, la hora de inicio del evento se expresa en una ecuación simple: 2x + 6 = x + 17 ¿A qué hora comenzó el evento?

La hora en que comienza el evento en los juegos olímpicos se representa como x

Por tanto: 2x + 6 = x + 17

Recopilar términos similares

2x - x = 17 - 6

x = 11 minutos

Por lo tanto, los eventos comienzan en 11 minutos.

7 0
3 years ago
The sugar content of the syrup in canned peaches is normally distributed. A random sample of n = 10 cans yields a sample standar
Serggg [28]

Answer:

The 95% confidence interval is given by:

3.30<σ<8.76

Step-by-step explanation:

1) Data given and notation

s=4.798 represent the sample standard deviation

\bar x represent the sample mean

n=10 the sample size

Confidence=95% or 0.95

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=10-1=9

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.025,9)" "=CHISQ.INV(0.975,9)". so for this case the critical values are:

\chi^2_{\alpha/2}=19.022

\chi^2_{1- \alpha/2}=2.700

And replacing into the formula for the interval we got:

\frac{(9)(4.798)^2}{19.022} \leq \sigma \frac{(9)(4.798)^2}{2.700}

10.892 \leq \sigma^2 \leq 76.736

Now we just take square root on both sides of the interval and we got:

3.30 \leq \sigma \leq 8.76

So the best option would be:

3.30<σ<8.76

7 0
3 years ago
Jade had $100 yesterday. Today she earns d dollars for babysitting. She now has $148. Write an equation to match how much money
ELEN [110]
100 + 48=148  so that means she got 48 dollars for babysitting 
8 0
3 years ago
Read 2 more answers
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