Question

What is the discriminant of the quadratic equation 0 = –x2 4x – 2?

Answer 1

Answer:

Step-by-step explanation:

Given is a quadratic equation of the form

$-x^2+4x-2$

WE know that for any quadratic equation of the form

$ax^2+bx+c=0$

the discriminant would be

$b^2-4ac$

The discriminant determines the nature of roots of the quadratic equation, namely, real, rational or equal roots.

Here we have for the given equation

discriminant = $4^2-4(-1)(-2)\\=16-8\\=8$

Thus we have discriminant as positive but not perfect square

Hence roots would be distinct, irrational and real.

Answer 2

The answer is down the page under ANSWER. here is a quick explanation first.

okay, i assume your equation is actually like this:

minus x squared plus 4 x minus

note: the proper way to type this electronically is: -x^2 + 4x - 2.



The equation you gave is known as a quadratic equation.

if you think about it, the generic (general) way of writing this quadratic equation is:

ax^2 + bx + c


a, b and c are just numbers

eg.

2x^2 + 7x + 4

looking at the general equation above

a is 2
b is 7
c is 4

you can put negatives in as well, to find out a, b and c

eg

-2x^2 - 6x - 12


so, what is a b and c?

a is -2 (must say its negative)
b is - 6 (must say negative)
c is - 12 ( again, remember its a negative number)

ANSWER

IF YOU JUST WANT THE ANSWER.

THE DISCRIMINANT IS:

4 squared minus (4 times -1 times -2)
this is 16 - 8
solution of discriminant is 8


explanation:

so, now we cleared that up.
in any quadratic equation ( like the equation you gave), the discriminant is (in general)


b2 - 4ac

use this to solve it for any quadratic equation for the discriminant