Hello!
Here's how much each person stacked:
Ronnie -- 0.25 of the 40 pizzas.
Mack -- 9/40
Kim -- 35% of the 40 pizzas.
Ada -- rest of the pizzas.
Now, the questions asks for who stacked the most pizzas.
First, find our how many pizzas they stacked out of 40.
40 × 0.25 = 10
40 × 35% = 14
10 + 9 + 14 = 33
40 - 33 = 7
This means that Ronnie stacked 10 pizzas, Mack stacked 9 pizzas, Kim stacked 14 pizzas, and Ada stacked 7 pizzas.
ANSWER:
Kim stacked the most pizzas since she stacked 14 of them.
Each person received one quarter, which can be written as 1/4 or 0.25.
The common difference is 2
Answer:
Step-by-step explanation:
From the information given,
Number of personnel sampled, n = 85
Mean or average = 6.5
Standard deviation of the sample = 1.7
We want to determine the confidence interval for the mean number of years that personnel spent in a particular job before being promoted.
For a 95% confidence interval, the confidence level is 1.96. This is the z value and it is determined from the normal distribution table. We will apply the following formula to determine the confidence interval.
z×standard deviation/√n
= 1.96 × 6.5/√85
= 1.38
The confidence interval for the mean number of years spent before promotion is
The lower end of the interval is 6.5 - 1.38 = 5.12 years
The upper end is 6.5 + 1.38 = 7.88 years
Therefore, with 95% confidence interval, the mean number of years spent before being promoted is between 5.12 years and 7.88 years
Answer:
270
Step-by-step explanation:
I am not sure if i am correct but i think you should divide 6,480 by 24 which is 270
