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Artist 52 [7]
3 years ago
5

josue earned $56.25 fixing a coding issue with a popular website.it took him a total of 4.5 hours to fix the issue.The equation

4.5x=56.25 can be used to find Josue hourly rate.What is Josue hourly rate?

Mathematics
1 answer:
Marina CMI [18]3 years ago
5 0
In your calculator
Divide 56.25 by 4.5










That should equal 12.50
To double check you can
12.50 x 4.5 = 56.25

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Select all expressions whose value is negative
il63 [147K]

Answer:

"2 + 2(-3)(7) = negative

-2(27 ÷ 9)+4= negative

(14 ÷ -2)(-6)= positive

(4 - 10) - ( 8 ÷ ( -2))= negative

Step-by-step explanation:

2 + 2(-3)(7) = -40

-2(27 ÷ 9)+4= -2

(14 ÷ -2)(-6)= 42

(4 - 10) - ( 8 ÷ ( -2))= -2"

5 0
3 years ago
HELP PLEASE <br><br>must show work <br><br>I have the answer just need to show work​
Kazeer [188]

Answer:

Step-by-step explanation:

To solve these equations involving variables and exponents we need to follow these steps.

1) We need to find out the factor that is common in the equation.

2) After taking common, solve the equation. We can add or subtract only those values that have same bases.

1) 8+6x^4

here we can see, both numbers are divisible by 2, so taking 2 common

=2(8/2 + 6x^4/2)\\= 2(4 + 3x^4)

It cannot be further simplified because both number donot have same bases.

3.4n^9 + 12 n

We can take 4n common

=4n(4n^9/4n + 12 n/4n)\\=4n(n^8 + 3)

5. -12a -3

Here -3 cam be taken common

= -3(-12a/-3 -3/-3)

= -3(4a +1)

7. 12n^5 + 16n^3

here the smallest power of n is n^3 so, we can take n^3 common and both coefficients are divisible by 4 so taking 4n^3 common

4n^3( 3n^2 + 4)

9. 5k^2 - 40k+10

Here we cannot take k common, as k is not a multiple of 10. For taking common it should be divisible by each value in the equation. But each value s divisible by 5 so, taking 5 common

=5(k^2 - 8k + 2)

11.-60 + 60n^2 +50n^3

Here we cannot take n common, as n is not a multiple of -60. For taking common it should be divisible by each value in the equation. But each value s divisible by 10 so, taking 10 common

=10(-6 + 6n^2 +5n^3)

13. -36n^3 -12n-28

Here we cannot take n common, as n is not a multiple of 28. For taking common it should be divisible by each value in the equation. But each value s divisible by -4 so, taking -4 common

=-4(9n^3 + 3n +7)

15. 63n^3+81n+18

Here we cannot take n common, as n is not a multiple of 18. For taking common it should be divisible by each value in the equation. But each value s divisible by 9 so, taking 9 common

=9(7n^3 + 9n + 2)

17. -24a^2b^2 + 36ab-60a

=6a(-4ab^2+6b-10)

3 0
3 years ago
What are the coordinates of the endpoints of the midsegment for △JKL that is parallel to KL⎯⎯⎯⎯⎯? Enter your answers in the boxe
algol [13]
The points you are looking for are the midpoints of segments JL and JK.
J(-2, -1), K(4, -5), L(0, -5)

The midpoint of segment JL is

(-2 + 0)/2, (-1 + (-5))/2) = (-2/2, -6/2) = (-1, -3)

The midpoint of segment JK is

(-2 + 4)/2, (-1 + (-5))/2) = (2/2, -6/2) = (1, -3)

Answer: The coordinates are (-1, -3), (1, -3)
6 0
3 years ago
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which of the following equations represents a linear function? A. y=3X^2 B. Y=2- 6/x C. y= x +6 D.y=1/2x+3
grigory [225]
<span> C. y= x +6 is the linear equation</span>
4 0
3 years ago
How to determine if a function is even or odd calculus?
aalyn [17]
A function f(x) is even if f(-x)=f(x), and is odd if f(-x)=-f(x).

Example:

f(x)=x^2 is even, since f(-x)=(-x)^2=x^2=f(x).

g(x)=x^3-x is odd, since g(-x)=(-x)^3-(-x)=-x^3+x=-(x^3-x)=-g(x).
6 0
3 years ago
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