Answer:
The maximum height of the projectile is 90 ft
Step-by-step explanation:
Here, we want to get the maximum height reached by the projectile
The answer here will be the y-coordinate value of the vertex form of the given equation
so firstly, we have to write the equation in the vertex form
We have this as;
y = -16t^2 + 64t + 26
That will be;
y = a(x-h)^2 + k
y = -16(x-2)^2 + 90
where the vertex of the equation is;
(-h,k)
K
in this case is 90 and thus, that is the maximum height of the projectile
The product of multiplying the ones digit of 59 by 853 is 7677 and the product of multiplying the tens digit of 59 by 853 is 42650 and the final product is 50327
<h3>How to determine the product of the numbers?</h3>
The numbers are given as
853 and 59
By using the standard algorithm i.e. the partial product method, we have the following equation
853 * 59 = 853 * (50 + 9)
Open the bracket
So, we have
853 * 59 = 853 * 50 + 853 * 9
Evaluate the products
So, we have
853 * 59 = 42650 + 7677
The above means that the product of multiplying the ones digit of 59 by 853 is 7677 and the product of multiplying the tens digit of 59 by 853 is 42650
Next, we evaluate the sum
853 * 59 = 50327
This means that the final product is 50327
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when you divide 2 fractions, you reverse the second fraction then use multiplication
3/5 divided by 3/15 becomes
3/5 x 15/3 = 45/15 = 3
Answer: 2/3, 2:3, and 2 to 3
Explanation: there are three different ways to write ratios - using fractions, semi colons, and the word “to”
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