If a secant<span> and a </span><span>tangent of a circle </span><span>are drawn from a point outside the circle, then the product of the lengths of the secant and its external segment equals the square of the length of the tangent segment.
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y</span>² = 7(15+7)
<span>y</span>² = 7*22
<span>y</span>² = 154
<span>y = </span>√154
<span>y = 12.4 </span>← to the nearest tenth<span>
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1,234
One thousand
Two hundred
Thirty four
The function or x intercept is 6
25x^2 = 16
divide each side by 25
x^2 = 16/25
take the square root of each side
sqrt (x^2) = +- sqrt(16/25)
x = +- sqrt(16)/sqrt(25)
x = +- 4/5
x = 4/5, - 4/5
