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nadya68 [22]
3 years ago
12

Can i get some help with these 2 problems

Mathematics
1 answer:
denis-greek [22]3 years ago
8 0
I hope this helps you

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iragen [17]
I think it’s b.5. Hope this helps. :)
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4 years ago
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The length of a rectangle is 1 less than twice the width.
vladimir1956 [14]

w-width\\2w-1-length\\w(2w-1)=2w^2-w-the\ area\\28\ ft^2-the\ area\\\\\text{The equation:}\\\\2w^2-w=28\qquad\text{subtract 28 from both sides}\\\\2w^2-w-28=0\\\\2w^2-8w+7w-28=0\\\\2w(w-4)+7(w-4)=0\\\\(w-4)(2w+7)=0\iff w-4=0\ \vee\ 2w+7=0\\\\w-4=0\qquad\text{add 4 to both sides}\\\boxed{w=4}\\\\2w+7=0\qquad\text{subtract 7 from both sides}\\2w=-7\qquad\text{divide both sides by 2}\\w=-3.5

7 0
3 years ago
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I need help please who ever do this one question there are a real one :(
Phoenix [80]

Answer:

i think it is B hope it help

Step-by-step explanation:

3 0
3 years ago
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Is this right?? please help!
Ganezh [65]

Answer:

  6 < x < 8

Step-by-step explanation:

The compound inequality in this instance represent the "and" condition, not the "or" condition.* We might solve it like this.

  -47 > 1 -8x > -63 . . . . given

Multiply by -1:

  47 < -1 +8x < 63

Add 1:

  48 < 8x < 64

Divide by 8:

  6 < x < 8

______

* You can tell this is the case by looking at the ends of the given statement:

  -47 > -63 . . . . a true statement, so the solution set will be an intersection, not a union.

4 0
3 years ago
What property for each step?​
PolarNik [594]
For the first one it’s subtraction property of equality
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3 years ago
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