Pleaser answer CORRECTLY , WILL MARK BRAINLIEST !!!!!!!!!

Mathematics

1 answer:

Nataly [62]3 years ago

5 0

Answer:

Step-by-step explanation:

-3a + 6b = a + 4b

-4a + 6b = 4b

-4a = -2b

a = -2b/-4

f(a) = -b/2

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Marcie bought a total of 20 used books and cds during a yard sale for a total of 54.50$. of books cost 1.50$ each and cds 5$ eac

melomori [17]

Let numbers of books be 'b' and numbers of CDs be 'c'

We can set up two equations:
Equation [1] ⇒ $b+c=20$
Equation [2] ⇒ $1.50b+5c=54.50$

We are solving for the number of books and the number of CDs bought

When we have two equations in terms of two different variables; $b$ and $c$ , that we need to solve, then this becomes a simultaneous equation problem.

First, rearrange Equation [1] to make either $b$ or $c$ the subject:
$b+c=20$
$b=20-c$

Then we substitute $b=20-c$ into Equation [2]
$1.50b+5c=54.50$
$1.50(20-c)+5c=54.50$
$30-1.50c+5c=54.50$
$5c-1.5c=54.50-30$
$3.5c=24.50$
$c=7$

Now we know the value of $c$ which is $c=7$ , substitute this value into $b=20-c$ we have $b=20-7=13$

Answer:
Numbers of books = 13
Numbers of CDs = 7

5 0

3 years ago

8^(3x-1)=2^8 <br><br>Solve for x

Yuri [45]

$8^{(3x-1)}=2^8 \\\\ 2^{3(3x-1)}=2^8 \\\\ 3(3x-1)=8 \\\\ 9x-3=8 \\\\ 9x=8+3 \\\\ 9x=11 \\\\ \boxed{x=\frac{11}{9}}$