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My name is Ann [436]
3 years ago
15

Enter the equation of the circle described below. Center (3, -2), radius = 5

Mathematics
1 answer:
VMariaS [17]3 years ago
8 0
Equation of a circle:
(x - h)^2 + (y - k)^2 = r^2

where (h,k) is the center and r = radius

(x - 3)^2 + (y + 2)^2 = 25
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Plz help me and explain it.
Schach [20]
The second windsurfer is going faster cuz 5 meters = 16.4042.
6 0
3 years ago
Needs help with this!!!
barxatty [35]

Answer:

y^1=-1(x-1)+(1+9)

Step-by-step explanation:

y=-1x+1\ \ == > \ \ y^1=-1(x-1)+(1+9)

-1 horizontally = 1 units left (the x-axis)

9 vertically = 9 units up (y-axis)

*Black line: is the preimage

*Red line is the translation

Hope this helps!

6 0
3 years ago
There are 1,570 souvenir paperweights that need to be packed in boxes. Each box will hold 17 paperweights. How many boxes will b
arlik [135]

Answer:

93 boxes will be needed.

Step-by-step explanation:

Divide 1570 ÷ 17

This gives the answer 92.35

So 92 boxes won't be enough. 0.35 of a box itsn't helpful in the real world. So you need 93 boxes.

8 0
2 years ago
Solve the system using elimination. 3x + 3y = –9 3x – 3y = 21
scoundrel [369]

Answer:

y=-5,x=2

Step-by-step explanation:

3x+3y=-9________________eqn 1

3x-3y=21________________eqn 2

using elimination method

3x+3y=-9

-

3x-3y=21

subtract equation 2 from equation 1

0+6y=-30

6y=-30

y=-30/6

y=-5

substitute the value of y in equation 1

3x+3y=-9

3x+3(-5)=-9

3x-15=-9

3x=-9+15

3x=6

x=6/3

x=2

6 0
3 years ago
A Pew Internet poll asked cell phone owners about how they used their cell phones. One question asked whether or not during the
EastWind [94]

Answer:

a) \hat p=\frac{471}{1024}=0.460

The standard error is given by:

SE= \sqrt{\frac{\hat p(1-\hat p)}{n}}=\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0156

And the margin of error is given by:

ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}=1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0305

b) The 99% confidence interval would be given by (0.429;0.491)

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Data given and notation  

n=1024 represent the random sample taken    

X=471 represent the people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

\hat p=\frac{471}{1024}=0.460 estimated proportion of people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering    

p= population proportion of people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

Part a

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

The standard error is given by:

SE= \sqrt{\frac{\hat p(1-\hat p)}{n}}=\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0156

And the margin of error is given by:

ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}=1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0305

Part b

If we replace the values obtained we got:

0.460-1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.429

0.460+1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.491

The 99% confidence interval would be given by (0.429;0.491)

8 0
3 years ago
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