Ask question

Ask question

All categories

2 years ago

6

Harry's mother makes cakes for a local resturant. She buys flour and sugar in large amounts. She has 157.86 pounds of flour and

82.69 pounds of sugar. If she uses 15 pounds of flour and 8 pounds of sugar each day, for about how many days will the flour last?

2 answers:

xz_007 [3.2K]2 years ago

4 0

10 1/2 days for the flour and 10 or 10 1/2 for the sugar too

dolphi86 [110]2 years ago

3 0

Should last up to 10 days for both

You might be interested in

Alborosie

180-92=88 the answer is 88 because a line is equal to 180 degrees and you got one angle equaling 92 degrees so you just subtract 180 minus 92, getting you angle 8 to be 88 degrees

3 0

2 years ago

Read 2 more answers

2627 divided by 22 withR

MrMuchimi

Answer:

119 r 9

Step-by-step explanation:

4 0

1 year ago

Shurley bought a new bed and now needs to find pillows, sheets, and a comforter for it. She wants to have black or white pillows

Firlakuza [10]

There are 2 different pillows, 2 different sheets and 3 different comforters.

Multiply all the choices together to find all the combinations:

Total combinations: 2 x 2 x 3 = 12

There are 12 different combinations.

8 0

2 years ago

Read 2 more answers

I have a math problem that is stumping me and other people. Do you always multiple before dividing or do you work left to right?

swat32

It is customary to work left to right, however that is not a rule. In order of operations, the actual rule is that multiplication/division occurs after parentheses, exponents, and before addition/subtraction...

PEMDAS order of operations

Parentheses, exponents, mutiplication/division, addition/subtraction.

6 0

2 years ago

Match the expression to the exponent property that you use first to simplify the expression.

IRINA_888 [86]

Step-by-step explanation:

$\dfrac{a^m}{a^n}=a^{m-n}\to\dfrac{h^\frac{3}{2}}{h^\frac{4}{3}}=h^{\frac{3}{2}-\frac{4}{3}}=h^{\frac{(3)(3)}{(2)(3)}-\frac{(2)(4)}{(2)(3)}}=h^{\frac{9}{6}-\frac{8}{6}}=h^{\frac{1}{6}}\\\\(a^m)^n=a^{mn}\to\bigg(p^\frac{1}{4}\bigg)^\frac{2}{3}=p^{\left(\frac{1}{4}\right)\left(\frac{2}{3}\right)}=p^\frac{2}{12}=p^\frac{1}{6}\\\\a^m\cdot a^n=a^{m+n}\to z^\frac{3}{4}\times z^\frac{5}{6}=z^{\frac{3}{4}+\frac{5}{6}}=z^{\frac{(3)(3)}{(4)(3)}+\frac{(5)(2)}{(6)(2)}}=z^{\frac{9}{12}+\frac{10}{12}}=z^\frac{19}{12}$

$\left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\to\bigg(\dfrac{x^2}{y}\bigg)^\frac{1}{3}=\dfrac{\left(x^2\right)^\frac{1}{3}}{y^\frac{1}{3}}=\dfrac{x^{(2)\left(\frac{1}{3}\right)}}{y^\frac{1}{3}}=\dfrac{x^\frac{2}{3}}{y^\frac{1}{3}}$

3 0

2 years ago