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Westkost [7]
3 years ago
14

Solve the system using elimination. 3x + 3y = –9 3x – 3y = 21

Mathematics
1 answer:
scoundrel [369]3 years ago
6 0

Answer:

y=-5,x=2

Step-by-step explanation:

3x+3y=-9________________eqn 1

3x-3y=21________________eqn 2

using elimination method

3x+3y=-9

-

3x-3y=21

subtract equation 2 from equation 1

0+6y=-30

6y=-30

y=-30/6

y=-5

substitute the value of y in equation 1

3x+3y=-9

3x+3(-5)=-9

3x-15=-9

3x=-9+15

3x=6

x=6/3

x=2

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Answer:

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Step-by-step explanation:

Given inequality is \[−7\geq13−5x\]

Simplifying:

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\[=>5x\geq20\]

\[=>x\geq \frac{20}{5}\]

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3 years ago
What are the zeros of the following quadratic equation: y = 6x2 - 17x - 3
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Answer:

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Step-by-step explanation:

Hi there!

y = 6x^2 - 17x - 3

Factor by grouping:

y = 6x^2 - 18x+1x - 3\\y = 6x(x- 3)+1x - 3\\y = 6x(x- 3)+(x - 3)\\y = (6x+1)(x- 3)

Let y=0. Apply the zero product property:

0 = (6x+1)(x- 3)

6x+1=0\\6x=-1\\\\\displaystyle x=-\frac{1}{6}

AND

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I hope this helps!

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