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lys-0071 [83]
3 years ago
14

There are 20 bags filled with coins that all look alike. The coins in 19 of the bags are authentic and weigh 10 ounces each. The

coins in one of the bags are counterfeit and weigh 11 ounces each. With only one weighing on a scale, how can you determine which bag contains the counterfeit coins
Mathematics
1 answer:
irakobra [83]3 years ago
6 0
It will come out to a flat number like 10 20 30 40 ect and the counterfeit will have a 1 at the end such as 11 21 31 41.
Hope i Helped
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Is the given number a solution of the equation?<br> 8=2+3; 10
kykrilka [37]

Answer:

No.

Step-by-step explanation:

8 doesn't equal 0 on the very right, which means it's not a solution to the equation.  So therefore, it is false based on the equation.

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Help i will give brainlist.
Mekhanik [1.2K]

Answer:

3m^4  

Step-by-step explanation:

the third one

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In the parallelogram above what is the value of x?Please explain for brainlest
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E: 36 because the total degrees of a parallelogram is 360 and opposite angles of parallelogram’s are equal so the angles diagonal from the given ones are the same. So the corners are 3x, 2x, 3x, 2x. In total that is 10x. 360/10 = 36
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2 years ago
A fan is marked up 40% on the original price. The original price was $20. What is the new price of the fan before sales tax?
JulsSmile [24]

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$28

Step-by-step explanation:

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3 years ago
On a coordinate plane, parallelogram R S T U has points (negative 4, 4), (2, 6), (6, 2), and (0, 0). What is the area of paralle
Ad libitum [116K]

Answer:

The area of the parallelogram is;

32 square units

Step-by-step explanation:

The given parameters are;

The coordinates of the parallelogram RSTU = R(-4, 4), S(2, 6), T(6, 2), and U(0, 0)

We note that the area of a parallelogram = Base length × Height

From the drawing of the parallelogram RSTU, we have;

The base length = The length of \overline {TU} = The length of \overline {SR} = √((2 - (-4))² + (6 - 4)²) = 2·√10

The height of a parallelogram is perpendicular to its base length = The line \overline {VT}

∴ Where, the slope of the base length = m, the slope of the height = -1/m

The slope, 'm' of \overline {SR} = (6 - 4)/(2 - (-4)) = 1/3

Therefore, the slope of the height = -1/(1/3) = -3

We note that a point on the height is the point 'T', therefore, the equation of the line in point and slope form is therefore;

y - 0 = -3·(x - 0)

∴ y = -3·x

Therefore, the coordinates of the point 'V' is given by the simultaneous solution of the equations of \overline {SR} and \overline {VT}

The equation of the line \overline {SR} in point and slope form from the point 'R' and the slope 'm = 1/3' is given as follows;

y - 4 = (1/3) × (x - (-4)) = (1/3) × (x + 4)

y = x/3 + 4/3 + 4 = x/3 + 16/3

y = x/3 + 16/3

We then have the coordinate at the point 'V' (x, y) is given as follows;

-3·x = x/3 + 16/3

-9·x = x + 16

-10·x = 16

x = -16/10 = -1.6

x = -1.6

∴ y = -3·x = -3 × -1.6 = -4.8

y = 4.8

The coordinate at the point, V = (-1.6, 4.8)

The length of the line \overline {VT} = The height of the parallelogram = √((-1.6 - 0)² + (4.8 - 0)²) = 8/5·√10

The height of the parallelogram = 8/5·√10

The area of the parallelogram, A = Base length × Height

∴ A = 2·√(10) × 8/5·√(10) = (16/5) × 10 = 32

The area of the parallelogram, A =  32 square units.

6 0
3 years ago
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