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murzikaleks [220]
3 years ago
9

Six math books, four physics books and three chemistry books are arranged on a shelf.

Mathematics
1 answer:
katrin [286]3 years ago
7 0

Answer:

622,080

Step-by-step explanation:

The total number of subjects is 3

= 3×2×1

= 6

Six maths book

= 6×5×4×3×2×1

= 720

Four physics book

= 4×3×2×1

= 24

Three chemistry book

= 3×2×1

= 6

6×720×24×6

= 622,080

Hence if the books are grouped together 622,080 arrangement is possible

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Find the volume of 5yd,4yd,4yd,2yd,1.5yd,​
OleMash [197]

Answer:

240

Step-by-step explanation:

Multiply them altogether.

5 x 4 x 4 x 2 x 1.5 = 10 x 24 = 240

6 0
3 years ago
Solve for x. She<br> - 7/2x+ 1/2= 31/6
Lilit [14]
I think it is -3/4 im pretty sure
8 0
3 years ago
a triangle has a perimeter of 49 inches. the medium side is 7 more than the short side, and the longest side is 5 times the leng
slavikrds [6]
Short side length = x
Medium side = x + 7
Long side = 5x
Total 49, so
x + x + 7 + 5x = 49
If you combine like terms:
7x + 7 = 49
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4 0
3 years ago
Read 2 more answers
Please helppp
tangare [24]

Answer:

Adult: 50 tickets

Child: 34 tickets

Step-by-step explanation:

Let a be the amount of adult tickets

Let c be the amount of child tickets

Equation:

a + c = 84

14a + 9c = 1,006

Step 1: Multiply a + c = 84 with -9, to canceled c.

-9 (a + c = 84)    →  -9a - 9c = -756

14a + 9c = 1006 → 14a + 9c = 1006

Step 2: Combined the 2 equation together, and solved it.

-9a - 9c = -756

<u>14a + 9c = 1006</u>

       <u> 5a</u> = <u>250</u>

        5        5

           a = 50

Step 3: Plug 50 into the one of the equation, and solved it.

a + c = 84 → 50 + c = 84

                  <u>-50         -50</u>

                            c = 34

Answer: Adult tickets (a) = 50 and Child tickets (c) = 34

To check the answer plug the two number into the equation ( Make sure to add 50 for a and 34 for c).

3 0
3 years ago
A radioactive substance decays exponentially. A scientist begins with 190 milligrams of a radioactive
worty [1.4K]

Answer: 65.1 (mg)

Step-by-step explanation:

y=190*e^{-a*t}\\\\Calculate\ a:\\\\t=33,y=95(mg)\\\\190*e^{-a*33}=95\\\\e^{-a*33}=0.5\\\\-a*33=ln(0.5)\\\\a=\dfrac{ln(\dfrac{1}{2}) }{-33} \\\\a=0,02100... \approx{0.021}\\\\If\ t=51\ h, y=190*e^{-0.02100*51}=65.09167...\approx{65.1}

6 0
3 years ago
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