A rectangle has dimensions 10 cm by 6 cm. determine the measures of the angles at the point of where the diagonals intersect
1 answer:
See the attached figure to better understand the problem
we know that
in the triangle ABC
tan(alfa/2)=AC/BC----> 5/3
so
(alfa/2)=arctan (5/3)---------> 59.0362°
alfa=2*59.0362--------> alfa=118.07°
alfa+beta=180°----------> because are supplementary angles
beta=180-118.07-------> beta=61.93°
the answer is
the angles are
alfa=118.07°
beta=61.93°
we know that
in the triangle ABC
tan(alfa/2)=AC/BC----> 5/3
so
(alfa/2)=arctan (5/3)---------> 59.0362°
alfa=2*59.0362--------> alfa=118.07°
alfa+beta=180°----------> because are supplementary angles
beta=180-118.07-------> beta=61.93°
the answer is
the angles are
alfa=118.07°
beta=61.93°
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Answer:
376.991 cm²
Step-by-step explanation:
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= 50π + 70π
= 120π
= 376.9911184... ≈ 376.991
<h2>Derive Surface Area of A Cylinder</h2>If you take a look at a net of a cylinder, you can see it is composed of two circles(bases) and a rectangular strip with the length of the diameter of the circle
The formula for the area of a circle = πr², and since there are 2, it is 2πr²
The formula for circumference of a circle = 2πr, and since we are multiplying that by the height by the height of the cylinder, it is 2πrh
∴ 2πr² + 2πrh
