See the attached figure to better understand the problem
we know that
in the triangle ABC tan(alfa/2)=AC/BC----> 5/3 so (alfa/2)=arctan (5/3)---------> 59.0362° alfa=2*59.0362--------> alfa=118.07° alfa+beta=180°----------> because are supplementary angles beta=180-118.07-------> beta=61.93°
the answer is the angles are alfa=118.07° beta=61.93°