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kupik [55]
3 years ago
6

478 × 965 in distributive property

Mathematics
2 answers:
kakasveta [241]3 years ago
4 0
478(900) + 478(95)

Hope this helps!
olya-2409 [2.1K]3 years ago
3 0
(400x900)+(70x60)+(8x5)
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How to find the area under the standard normal curve between z 1.5 and z 2.5?
alisha [4.7K]
It is possible to calculate mathematically the area under the normal curve between any two values of z.
However, tables/software have been developed to give the areas under the normal curve to the left of particular values of z.  The function is the probability of Z<z, or P(Z<z).
The area between two values z1 and z2 (where z2>z1) is therefore 
P(Z<z2)-P(Z<z1).

For example, to find the area between  z1=1.5, z2=2.5
is 
P(Z<2.5)-P(Z<1.5)
=0.99379-0.93319
=0.06060

(above values obtained by software, such as R)
For example, the value P(Z<2.5) can be calculated using
P(Z<2.5)=erf(2.5/sqrt(2))/2+1/2
where erf(x) is a mathematical function that does not have an explicit formula (calculated by summation of series, or tabulated).
8 0
3 years ago
Graph the equation by plotting three points. if all three correct, the line will appear. -y=x+0?
kicyunya [14]

━━━━━━━☆☆━━━━━━━

▹ Answer

<em>(-1, 1) (-2, 2) (-3, 3)</em>

▹ Step-by-Step Explanation

You can use a graphing calculator to find the points. Attached is an image.

Hope this helps!

- CloutAnswers ❁

!

━━━━━━━☆☆━━━━━━━

6 0
3 years ago
A seagull flying in the air over water drops a crab from a height of 45 feet.The distance the crab is from the water as it falls
jonny [76]
For the seagull to catch the crab, h(t)=g(t) so:

-16t^2+45=-13t+23  add 16t^2 to both sides

45=16t^2-13t+23  subtract 45 from both sides

16t^2-13t-22=0  using the quadratic equation:

t=(13±√1577)/32, since t>0

t=(13+√1577)/32 seconds

t≈1.65 seconds (to nearest hundredth of a second)

And the height that this occurs using either original equation is:

h((13+√1577)/32)≈1.59 ft (to nearest hundredth of a foot)
7 0
3 years ago
Joe's Ice Cream Shop has 7/8 of a gallon of vanilla ice cream left. They use 1/12 of a gallon of ice cream to make one milkshake
Vadim26 [7]

Answer:

Ten and a Half milkshakes can be prepared from the available amount of ice cream.

Step-by-step explanation:

The total vanilla ice cream = 7/8 gallons

Ice cream used for 1 milkshake = 1/12 gallon

Now, total number of milkshakes possible = \frac{\textrm{Total availibility of ice cream}}{\textrm{Ice cream used for each milkshake}}

= \frac{\frac{7}{8} }{\frac{1}{12} }  = \frac{7}{8}  \times \frac{12}{1}  = 10.5

Hence ten and a half milkshakes can be prepared from the available amount of ice cream.

8 0
3 years ago
Read 2 more answers
How do you make a equation with 2/3 X3
Marrrta [24]
Do you mean (2/3) times 3X or is x a multiplication symbol
8 0
3 years ago
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