I need help with this exponential function problem, please show work :)

Mathematics

1 answer:

andreev551 [17]4 years ago

8 0

Answer:

a = 12. b =1/6. g(x) = 12(1/6)^x

Step-by-step explanation:

g(x) =a * b^x.

First we should use the give values to us in the table which are x=0 then g(x) = 12 and if x =1, then g(x) = 2. We should plug in the value where x = 0 since any value to the power of 0 is 1. 12= a *b^0. 12=a *1. Then we will get the value of a which is 12. Then we plug in our second given value to find b. 2 = 12 * b^1. First we will divide both sides by 12 to find b. 2/12 = 1/6. since any value to the power of 1 is itself then b =1/6. Then you will have a = 12. b =1/6 so g(x) = 12(1/6)^x

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Jessica was given the area and the length of the base of a triangle. A = 17.5 units, b = 5 units. She solved the formula for are

pychu [463]

Answer:

She messed up the equation, A= B x h, she changed it midway, and also, you need to add the one half to make the equation valid

Step-by-step explanation:

A=1/2 x b xh

17.5 = 1/2 x 5 x h

35=5h (multiply both sides by 2 to get rid of one half)

35/5 = 5h/5

7=h

The height of the triangle is 7 units

Please mark me brainliest, it really helps!

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2 years ago

Hey there I need some assistance need on this problem. What do I mean by checkpoints and how am I supposed to find the y-interce

MakcuM [25]

Slope Formula: y2 - y1 / x2 - x1

(m and slope represent the same quantity)

m = 1 - - 5 / -4 - 0

m = 1 + 5 / -4

m = 6 / -4

m = -3/2

Now that we know the slope, we can plug the slope and one of our points into slope-intercept form (y = mx + b) and solve for b. I will be using the point (-4,1).

y = -3/2x + b

1 = -3/2(-4) + b

1 = 6 + b

b = -5

In point form, the y-intercept is (0, -5).

Therefore, to get the equation all we need to do is plug in our slope and b-value to slope-intercept form.

Equation: y = -3/2 x - 5

To check the point (-6, -14) we plug it into our equation and see if the two sides are equal.

-14 = -3/2(-6) - 5

-14 = 9 - 5

-14 = 4

-14 does not equal 4, therefore the point is NOT on the line.