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Marizza181 [45]
3 years ago
15

Please help me this one is long so ill give 25 points

Mathematics
1 answer:
nadezda [96]3 years ago
8 0

Answer:

Step-by-step explanation:

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g My Notes Water flows from the bottom of a storage tank at a rate of r(t) = 200 − 4t liters per minute, where 0 ≤ t ≤ 50. Find
Arada [10]

Answer:

4,200 liters

Step-by-step explanation:

The flow rate is given by:

r(t) = 200 - 4t

Integrating the flow rate expression from t=0 to t=30 minutes, yields the total volume that flows out of the tank during that period:

\int\limits^{30}_0 {r(t)} = \int\limits^{30}_0 {(200 - 4t} )\, dt \\V=(200t - 2t^2)|_0^{30}\\V= (200*30 -2*30^2)-(200*0 -2*0^2)\\V=4,200\ liters

4,200 liters of water flow from the tank during the first 30 minutes.

3 0
3 years ago
I need help with this​
Ulleksa [173]
No, tahts the answer
8 0
3 years ago
Perform the indicated operation and write the answer in the form a + bi. (–1 + 5i) + (3 + 7i)
pashok25 [27]

Answer:

12i + 2

Step-by-step explanation:

Combine like terms.

-1 + 3 = 2

5i + 7i = 12i

12i + 2 is your answer.

~

5 0
3 years ago
In 2003, there were about 5.8078 X 10^8 people using the Internet in the world and about 1.6575 X 10^8 of these people were in t
lianna [129]

Answer:

28.5%  Internet users in 2003 were in the United States.    

Step-by-step explanation:

We are given the following in the question:

Number of people using the internet =

5.8078 \times 10^8

Number of people in United States =

1.6575 \times 10^8

Percent of Internet users in 2003 were in the United States =

=\dfrac{\text{Number of users in United States}}{\text{Number of internet user in world}}\times 100\%\\\\=\dfrac{ 1.6575 \times 10^8}{5.8078 \times 10^8}\times 100\%\\\\=28.5\%

Thus, 28.5%  Internet users in 2003 were in the United States.

6 0
3 years ago
Help a girl out please!
NeX [460]
Even function
(unchanged under reflection over y-axis)

Hope this helped :)
4 0
2 years ago
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