How to solve 11x-13y=89 and -11x+13y=107 by substitution

1 answer:

8 0

$\left\{\begin{array}{ccc}11x-13y=89&/+13y\\-11x+13y=107&/\cdot(-1)\end{array}\right\\\\\left\{\begin{array}{ccc}11x=13y+89\\11x-13y=-107\end{array}\right\\\\substitute:\\\\(13y+89)-13y=107\\13y-13y+89=107\\89=107-FLASE\\\\Answer:No\ solution\ (x;\ y\in\O)$

You might be interested in

Which inequality is represented by this graph? (0, 1) (6,0)

lawyer [7]

Answer:

Hope this isn't too late. The Answer Is D.

Step-by-step explanation:

The graph line becomes dotted when the inequality is less than or greater than, never less than or equal to./ greater than or equal to. This leaves to choices: B and D. D is the correct answer because the way the shading is going. because the shading is going up that means that the inequality is greater than.

4 0

3 years ago

Read 2 more answers

4 men can finish a job in 7 days how many more people are needed to finish the job in 4 days?

Luden [163]

Answer:

this makes no sense but i already answered so ima say 1

Step-by-step explanation:

im so sorry

7 0

3 years ago

If m is a common divisor of x and y, then x/y = (x ÷ k)/______

myrzilka [38]

Answer:

$\frac{x}{y} = \left(\frac{x}{y} \right)\cdot 1 = \left(\frac{x}{y}\right)\cdot \left(\frac{m}{m} \right) = \frac{\frac{x}{m} }{\frac{y}{m} }$

Step-by-step explanation:

The common divisor is the greatest natural number so that two or more natural numbers have no remainder. If $m$ is a common divisor of $x$ and $y$ , then $p = \frac{x}{m}$ and $q = \frac{y}{m}$ , where $p$ , $q$ $\in \mathbb{Z}$ . Then, we have the following expression: