Answer:
parallel
Step-by-step explanation:
Parallel lines have equal slopes.
Calculate the slopes m using the slope formula
m = 
with (x₁, y₁ ) = (- 1, 2) and (x₂, y₂ ) = (2, 3)
m = 
= 
Repeat with (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (3, 1)
m = 
=
Since slopes are equal then parallel
We must look at this question in steps
The first half of the journey is travelled at 40 km/h
Half of 100km is 50 km
Using the formula
Distance = Speed x Time
Speed = Distance / Time
Time = Distance / Speed
We can work out the time:
50km / 40km/h = 1.25 hours
Next we look at the second half of the journey
50km at 80km/h
50km / 80km/h = 0.625 hours
Add together both times to work out how long the entire journey took
1.25 + 0.625 = 1.875 hours
Using the Speed formula from before
Speed = 100km / 1.875 =
53 1/3 km/h or 53.3 recurring km/h
GCF= 1
FACTORED VERSION = (X-1) (2X+3)(X+2)
B C and E have a unit rate of 12 yards or second
Answer:
Yes; the compass was kept at the same width to create the arcs for points C and D.
Step-by-step explanation:
When bisecting a segment by hand the steps are:
-Place the compass on one of the endpoints and open the compass to a distance more than halfway across the segment.
-Swing an arc on either side of the segment.
-Keeping the compass at the same width, place the compass on the other endpoint and swing arcs on either side so that they intersect the first two arcs created.
-Mark the intersection points of the arcs and draw a line through those two points.
-The point where this new line crosses the given segment is the midpoint and divides the segment in half.
Its not b because segment c and d was created when you marked the intersection points of the arcs and just drew a line through those two points; They didn't use a straightedge. its not C because this does demonstrate how to bisect a segment by hand, Also the compass was kept at the same width to create the arcs for points C and D. Its not D because this does demonstrate how to bisect a segment by hand, Also a straightedge was not used to create segment CD.
