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Aliun [14]
3 years ago
12

Three varieties of coffee long dash— Coffee​ A, Coffee​ B, and Coffee C long dash— are combined and​ roasted, yielding a 51​-lb

batch of coffee beans. Twice as many pounds of Coffee​ C, which retails for ​$9.95 per​ lb, are needed as Coffee​ A, which sells for ​$15.99 per lb. Coffee B retails for ​$13.21 per lb. How many pounds of each coffee should be used in a blend that sells for ​$12.82 per​ lb?
Mathematics
1 answer:
asambeis [7]3 years ago
8 0
Let A, B and C be the number of pounds of each brand of coffee.
A+B+C=51 (weight) which is 3A+B=51 because C=2A, B=51-3A
15.99A+13.21B+19.90A=51×12.82=653.82 (cost) I’ve used C=2A
35.89A+13.21B=653.82
Substitute for B:
35.89A+13.21(51-3A)=653.82
35.89A+673.71-39.63A=653.82
3.74A=19.89, A=117/22 pounds, B=771/22 pounds, C=117/11 pounds.
Approximate weights are A: 5.32lb, B: 35.05lb, C: 10.64lb.
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A crew of loggers cleared 1/2 acre of lumber in 4 days. How long will it take the same crew to clear 2 3/4 acres of lumber?
krok68 [10]
Set up a proportion of acres to days. 1/2 acre is to 4 days as 2 3/4 acres is to x days.

x= # days to clear 2 3/4 acres
2 3/4 to improper fraction= 11/4

(1/2)/4 = (11/4)/x
cross multiply

(1/2 * x) = (4 * 11/4)
on the right, the 4 "cancels out"

1/2x= 11
divide both sides by 1/2

x= 11 ÷ 1/2
to divide fractions, multiply by reciprocal/inverse of 1/2

x= 11 * 2/1
x= 22 days

ANSWER: It would take 22 days to clear 2 3/4 acres.

Hope this helps! :)
6 0
4 years ago
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In which story is the answer to the question 0?
ioda

Hi there!

Answer:

The temperature at lunchtime is 0 degrees Celsius.

Step-by-step explanation:

This is because we started at -2 and when we add 2 that brings us back at 0 (or neutral).

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3 years ago
Convert the equation you found, T = A3/2, into a form without any rational exponents.
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Answer:

I agree with what the other person said :)

Step-by-step explanation:

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6 0
3 years ago
Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65
erma4kov [3.2K]

Answer:

Probability that the sample average is at most 3.00 = 0.98030

Probability that the sample average is between 2.65 and 3.00 = 0.4803

Step-by-step explanation:

We are given that the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65 and standard deviation 0.85.

Also, a random sample of 25 specimens is selected.

Let X bar = Sample average sediment density

The z score probability distribution for sample average is given by;

               Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 2.65

           \sigma  = standard deviation = 0.85

            n = sample size = 25

(a) Probability that the sample average sediment density is at most 3.00 is given by = P( X bar <= 3.00)

    P(X bar <= 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 2.06) = 0.98030

(b) Probability that sample average sediment density is between 2.65 and 3.00 is given by = P(2.65 < X bar < 3.00) = P(X bar < 3) - P(X bar <= 2.65)

P(X bar < 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z < 2.06) = 0.98030

 P(X bar <= 2.65) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{2.65-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 0) = 0.5

Therefore, P(2.65 < X bar < 3)  = 0.98030 - 0.5 = 0.4803 .

                                                                             

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4 years ago
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