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strojnjashka [21]
3 years ago
9

Here is a list of numbers.

Mathematics
1 answer:
adoni [48]3 years ago
6 0
A. 14 (7x2=14)

b. 8 (8x3=24)

c. 11 (no other numbers except 1 and 11 multiply to get 11)
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PLEASE HELP ASAP FOR TEST
Sauron [17]
i believe the answer is C.) 0.8840
if im wrong im sorry
5 0
3 years ago
A package of balloons contains 5 green, 3 yellow, 4 red, and 8 pink balloons. Suppose you reach in the package and choose one ba
Marianna [84]

Probability of choosing pink balloon is  \frac{2}{5}.

Step-by-step explanation:

Given,

Number of green balloons = 5

Number of yellow balloons = 3

Number of red balloons = 4

Number of pink balloons = 8

Total number of balloons = 5+3+4+8 = 20

To find the probability of pink balloon.

Formula

Probability of an even = number of outcomes ÷ total number of outcomes

So,

Probability of choosing pink balloon = \frac{8}{20} = \frac{2}{5}

6 0
3 years ago
Read 2 more answers
Factor completely 7x2-45x-28
MatroZZZ [7]

9514 1404 393

Answer:

  (x -7)(7x +4)

Step-by-step explanation:

The term -45x can be rewritten using factors of (7)(-28) that have a total of -45. Those factors would be ...

  (7)(-28) = (4)(-49)

7x^2 +4x -49x -28 = x(7x +4) -7(7x +4) = (x -7)(7x +4)

6 0
3 years ago
What is 1 2/25as a percent
Radda [10]
The answer for your problem is 48%
7 0
4 years ago
Read 2 more answers
A publisher reports that 65% of their readers own a laptop. A marketing executive wants to test the claim that the percentage is
muminat

Answer:

z=\frac{0.60 -0.65}{\sqrt{\frac{0.65(1-0.65)}{340}}}=-1.933  

The p value for this case can be calculated with this probability:

p_v =2*P(z  

For this case is we use a significance level of 5% we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true proportion is different from 0.65 or 65%. We need to be careful since if we use a value higher than 65 for the significance the result would change

Step-by-step explanation:

Information given

n=340 represent the random sample taken

\hat p=0.60 estimated proportion of readers owned a laptop

p_o=0.65 is the value that we want to test

z would represent the statistic

p_v{/tex} represent the p valueHypothesis to testWe want to check if the true proportion of readers owned a laptop if different from 0.65
Null hypothesis:[tex]p=0.65  

Alternative hypothesis:p \neq 0.65  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing we got:

z=\frac{0.60 -0.65}{\sqrt{\frac{0.65(1-0.65)}{340}}}=-1.933  

The p value for this case can be calculated with this probability:

p_v =2*P(z  

For this case is we use a significance level of 5% we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true proportion is different from 0.65 or 65%. We need to be careful since if we use a value higher than 65 for the significance the result would change

5 0
4 years ago
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