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2 years ago

Write the decimal for 1/8

Mathematics

1 answer:

Scilla [17]2 years ago

5 0

to solve you would have to divide 1 into 8. So using long division the answer would be 0.125

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In many parades, flowers are used to decorate the floats. The table below shows the number of flowers used in each row of a para

inessss [21]

Answer: C. n = 4r + 50

Step-by-step explanation:

The equation is in the form: y =mx + c

y is the number of flowers used.

x is the row number.

Solving for m. Pick any two points. (1, 54) and (2, 58)

m = (Y₂ - Y₁) / (X₂ - X₁)

= (58 - 54) / (2 - 1)

= 4

Solving for c. Use a point to fill up the formula and find c; (1, 54)

y = mx + c

54 = 4 * 1 + c

c = 54 - 4

c = 50

Formula will therefore be;

y = 4x + 50

or;

n = 4r + 50

5 0

2 years ago

The position equation for a particle is s of t equals the square root of the quantity t cubed plus 1 where s is measured in feet

vladimir1956 [14]

$\bf s(t)=\sqrt{t^3+1}
\\\\\\
\cfrac{ds}{dt}=\cfrac{1}{2}(t^3+1)^{-\frac{1}{2}}\cdot 3t^2\implies \boxed{\cfrac{ds}{dt}=\cfrac{3t^2}{2\sqrt{t^3+1}}}\leftarrow v(t)
\\\\\\
\cfrac{d^2s}{dt^2}=\cfrac{6t(2\sqrt{t^3+1})-3t^2\left( \frac{3t^2}{\sqrt{t^3+1}} \right)}{(2\sqrt{t^3+1})^2}\implies 
\cfrac{d^2s}{dt^2}=\cfrac{ \frac{6t(2\sqrt{t^3+1})-1}{\sqrt{t^3+1}} }{4(t^3+1)}$

$\bf \cfrac{d^2s}{dt^2}=\cfrac{6t[2(t^3+1)]-1}{4(t^3+1)\sqrt{t^3+1}}\implies 
\boxed{\cfrac{d^2s}{dt^2}=\cfrac{12t^4+12t-1}{4t^3+4\sqrt{t^3+1}}}\leftarrow a(t)\\\\
-------------------------------\\\\a(2)=\cfrac{215~ft^2}{44~sec}$

8 0

2 years ago

Read 2 more answers

5 pts

Vadim26 [7]

Answer:

An area or perimiter formula

Step-by-step explanation:

5 0

3 years ago

The area of a trapezoid is given by the formula A=h/2(a+b) .<br><br> Solve the formula for b.

Komok [63]

Answer:

(2A)/h -a =b

Step-by-step explanation:

A= [h(a+b)]/2 I rewrote the formula, because h and a+b are in the numerator.

2A=h(a+b) Multiply both sides of equation by 2

(2A)/h= a+b Divide both side by h

(2A)/h -a= b Subtract a from both sides

4 0

3 years ago

Y is directly proportional to square root of x<br> If y=56 when x=49 find,<br> y when x=81

STALIN [3.7K]

$\qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad \stackrel{\textit{constant of variation}}{y=\stackrel{\downarrow }{k}x~\hfill } \\\\ \textit{\underline{x} varies directly with }\underline{z^5}\qquad \qquad \stackrel{\textit{constant of variation}}{x=\stackrel{\downarrow }{k}z^5~\hfill } \\\\[-0.35em] \rule{34em}{0.25pt}$

$\stackrel{\begin{array}{llll} \textit{"y" directly}\\ \textit{proportional to }\sqrt{x} \end{array}}{y = k\sqrt{x}}\qquad \textit{we know that} \begin{cases} y = 56\\ x = 49 \end{cases}\implies 56=k\sqrt{49} \\\\\\ 56=7k\implies \cfrac{56}{7}=k\implies 8=k~\hfill \boxed{y=8\sqrt{x}} \\\\\\ \textit{when x = 81, what is "y"?}\hfill y=8\sqrt{81}\implies y=8(9)\implies y=72$

7 0

1 year ago