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sveta [45]
4 years ago
5

Combining transformations result in interesting designs. true false

Mathematics
1 answer:
Nadya [2.5K]4 years ago
4 0
True

because many thing who giv wonderful things
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Find the volume of the cube in centimeters3<br> While the cm is 5
Kaylis [27]

Answer:

125cm^3

Step-by-step explanation:

SO the formula for volume of a cube is

V=a^3

so just plug 5 in and you get

5^3

5*5*5= 125

Hope this helps

6 0
3 years ago
A flowerbed is to be 3m longer than its width.the flowerbed will have an area of 70m²​
melomori [17]
ANSWER
Yes, it is a quadratic equation which is x² + 3x - 70 = 0

SOLUTION

Area = Length × Width
Let x be the Length, L = x
Length is 3 cm longer than its width, thus, W = x + 3
The Area is equal to 70m², thus, A = 70m²

In Mathematical representation,
A = L × W
70 = (x)(x + 3)
70 = x(x) + x(3)
70 = x² + 3x
0 = x² + 3x - 70
4 0
3 years ago
I wmat to sleep been doing work for an hour help me out
Blizzard [7]

Answer:

A. 23, 37.....

B. 26, 42......

Step-by-step explanation:

have a great day!

3 0
3 years ago
Two chemical companies can supply a raw material. The concentration of a particular element in this material is important. The m
svp [43]

Answer:

As the calculated F lies in the acceptance region therefore we conclude that there is not sufficient evidence to support the claim that the variability in concentration may differ for the two companies. Hence Ha is rejected and H0 is accepted.

Step-by-step explanation:

As we suspect the variability of concentration F - test is applied.

n1=10    s1=4.7

n2=16      s2=5.8

And α = 0.05.

The null and alternate hypothesis are

H0: σ₁²=σ₂²       Ha:  σ₁²≠σ₂²

The null hypothesis is  the variability in concentration does not  differ for the two companies.

against the claim

the variability in concentration may differ for the two companies

The critical region F∝(υ1,υ2) = F(0.025)9,15= 3.12

and 1/F∝(υ1,υ2) = 1/3.77= 0.26533

where υ1= n1-1= 10-1= 9 and υ2= n2-1= 16-1= 15

Test Statistic

F = s₁²/s₂²

F= 4.7²/5.8²=0.6566

Conclusion :

As the calculated F lies in the acceptance region therefore we conclude that there is not sufficient evidence to support the claim that the variability in concentration may differ for the two companies. Hence Ha is rejected and H0 is accepted.

3 0
3 years ago
In one flip of 10 unbiased coins, what is the probability of getting 8 or more heads?
Maru [420]
Correct Answer: 0.0625
6 0
3 years ago
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