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3 years ago

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The ordered pairs (6,8), (9, 12), (x, 20), (18, y) represent a proportional relationship. Find the value of X and the value of Y

. Select the two correct answers.

1 answer:

sasho [114]3 years ago

7 0

Answer:

x=15 y=24

Step-by-step explanation:

This is because the rule is x goes up 3 y goes up 4

(9,12)->(x,20)

it skips one, so instead of adding 3 we add six

x=15

(15,20)->(18,y)

you follow the rule and 4.

Y=24

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Answer:

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Step-by-step explanation:

12y = 75 + 5x + 2x - 1

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12y = 74 + 7x

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7x = 12y - 74

divide both sides by 7:

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Answer: OPTION A

Step-by-step explanation:

The equation of the line in slope-intercept form is:

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A formula is expressed as D= a(2+kt). Express k in the terms of D, a and t? (Show work)

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When fishing off the shores of Florida, a spotted seatrout must be between 10 and 30 inches long before it can be kept; otherwis

Mademuasel [1]

Answer:

There is a 97.585% probability that a fisherman catches a spotted seatrout within the legal limits.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

The lengths of the spotted seatrout that are caught, are normally distributed with a mean of 22 inches, and a standard deviation of 4 inches, so $\mu = 22, \sigma = 4$ .

What is the probability that a fisherman catches a spotted seatrout within the legal limits?

They must be between 10 and 30 inches.

So, this is the pvalue of the Z score of $X = 30$ subtracted by the pvalue of the Z score of $X = 10$

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X = 10

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{10 - 22}{4}$

$Z = -3$

$Z = -3$ has a pvalue of 0.00135.

This means that there is a 0.9772-0.00135 = 0.97585 = 97.585% probability that a fisherman catches a spotted seatrout within the legal limits.

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