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CaHeK987 [17]
3 years ago
7

What is the negation of the statement "All burnt muffins are not edible"

Mathematics
1 answer:
rosijanka [135]3 years ago
7 0

Answer:

because they will taste bad because there burnt

Step-by-step explanation:

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Find the slope of the line through each pair of points (0,16)(4,-19)
Juliette [100K]
Use slope formula
(y1-y2)/(x1-x2)

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What are the solutions to the equation y2 – 1 = 48?
Furkat [3]

{y}^{2}  - 1 = 48 \\  {y}^{2}  = 49 \\ y =  \sqrt{49}  \\ y =  - 7 \: or \: 7

{y}^{2}  - 1 = 24 \\  {y}^{2}  = 25 \\ y =  \sqrt{25}  \\ y =  - 5 \: or \: 5

Hope this helps. - M
6 0
3 years ago
Given: ABCD is a trapezoid, AC ⊥ CD AB = CD, AC=the square root of 75 , AB = 5 Find: AABCD
Ugo [173]

In this attached picture according to the conditions of the problem we have an isosceles trapezoid and since we know that legs are equal (AD=BC=5 cm), we have to calculate bases and height in order to find the area. Working with the triangle BCD, we apply Pythagoras theorem and find that CD = \sqrt{75+25} = 10 cm. Since BDC is a right triangle, applying theorem for the area of triangles, we find that \frac{1}{2} * BF =  \frac{1}{2} * 5 * \sqrt{75} and BF= 0.5\sqrt{75}. Since ABCD is an isosceles trapezoid, triangles ADE and BFC are congruent with Angle Side Angle theorem. Then, DE=FC and with the help of Pythagoras theorem, DE=FC=2.5 cm. Then, AB=EF=5 cm and the area of the trapezoid is  A= BF *  \frac{AB+CD}{2} = 0.5  \sqrt{75}  * \frac{5+10}{2} = 18.75 \sqrt{3}   cm^{2}

3 0
3 years ago
In a class of 28 students, 19 have a cat and 6 have a dog. There are 5 students who do not have a cat or a dog. What is the prob
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Answer:

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3 0
3 years ago
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V=u+at u=2 a=15 t=1/5 what is the value of v
alukav5142 [94]

Answer and explanation:

V originally equals u + at, but when you plug in u, a, and t you get a number answer.

u = 2

a = 15

t = 1/5

Rewrite the expression with the numbers plugged in.

V = (2) + (15)(1/5)  <em>Multiply 15 by 1/5</em>

V = 2 + 3  <em>Add 2 and 3 together</em>

V = 5

<h2><u>So V would equal 5</u></h2>
7 0
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