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3 years ago

Find the slope of the line through each pair of points (0,16)(4,-19)

Mathematics

2 answers:

Alenkinab [10]3 years ago

7 0

(16+19)/(0-4)
35/-4
-8 3/4

Hope this helps :)

Juliette [100K]3 years ago

4 0

Use slope formula
(y1-y2)/(x1-x2)

(16 - -19)/(0 - 4) = 35/-4

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Which statement is correct?

ale4655 [162]

“Just follow your heart to find the answer” -someone

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3 years ago

Maggie's brother is 6 years younger than four times her age. The sum of their ages is 39. How old is Maggie?

poizon [28]

We can set Maggie's age to x

If her brother is six years younger than four times her age, than her brother must be equal to: 4x-6

Since the sum of their ages is 39, we can set up an equation.

(Sum of Maggie's age) + (sum of Maggie's brother's age) = 39

x + (4x -6) = 39

5x -6 = 39

5x = 45

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3 years ago

A box of cereal states that there are 87 calories in a 3-4cup serving. What is the unit rate for calories per cup? How many ca

riadik2000 [5.3K]

Answer: for 2 cups, There are 232 Calories.

Step-by-step explanation:

Step 1

Let the calories in one cup be represented as C

Therefore

3/4 x C = 87 calories

C = 87 X 4 / 3 = 116

unit rate is 116 calories per cup.

Step 2- Solving the number of calories in 2 cups

1 cup serving = 116 calories

2 cups servings = 116 x 2= 232 calories

3 0

3 years ago

It takes layla 2/5 hour to swim 1/2 mile what is the unit rate of miles that layla can swim per hour

Mazyrski [523]

Good Morning!

Distance = rate x time

1/2 mile = R x 2/5 hour

1/2=2/5R

/2/5 /2/5

R=1/2 x 5/2

R=1 1/4

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I hope this helps! :)

4 0

3 years ago

Al factorizar el trinomio cuadrado perfecto, obtenemos el siguiente resultado: (que no se como resolver) xd algun pro que sepa r

PolarNik [594]

Answer:

$\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2$

Step-by-step explanation:

<u>Trinomio Cuadrado Perfecto</u>

El producto notable llamado cuadrado de un binomio se expresa como:

$(a-b)^2=a^2-2ab+b^2$

Si se tiene un trinomio, es posible convertirlo en un cuadrado perfecto si cumple con las condiciones impuestas en la fórmula:

* El primer término es un cuadrado perfecto

* El último término es un cuadrado perfecto

* El segundo término es el doble del proudcto de los dos términos del binomio.

Tenemos la expresión:

$\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8$

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:

$\displaystyle a=\sqrt{\frac{100}{81}m^8p^{12}q^{16}z^2}$

$\displaystyle a=\frac{10}{9}m^4p^{6}q^{8}z$

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:

$\displaystyle b=\sqrt{\frac{1}{49}m^2p^2z^8$

$\displaystyle b=\frac{1}{7}mpz^4$

Nos cercioramos de que el término central es 2ab:

$\displaystyle 2ab=2\frac{10}{9}m^4p^{6}q^{8}z\frac{1}{7}mpz^4$

Operando:

$\displaystyle 2ab=\frac{20}{63}m^5p^7q^8z^5$

Una vez verificado, ahora podemos decir que:

$\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2$

5 0

2 years ago