★ Sigma Operator ★
Option C is the correct answer of the above summation series
Description -
Upper limit of sigma - ∞ [ where to stop ]
Lower Limit - 10 [ Where to start ]
Argument = n²
Hence we'll obtain - 100 + 121 + ... ∞
Answer:
Step-by-step explanation:
d) (-2 +4i) -( 3 + 9i) = -2 + 4i - 3 - 9i
= -2 - 3 + 4i - 9i
= -5 - 5i
e)3i(6 - 5i) = 3i *6 - 5i * 3i
= 18i - 15*i² {i² = -1}
= 18i -15*(-1)
= 18i + 15
= 15 + 18i
f) (-3 + 7i)(1 - 2i) = (-3)*1 - 2i * (-3) + 7i *1 - 2i* 7i
= -3 + 6i + 7i - 14i²
= -3 + 6i + 7i - 14*(-1)
= -3 + 6i+ 7i + 14
= 11 + 13i
Answer:
Step-by-step explanation:
Sine theorem: in any triangle, the ratio between a side and the sine of the opposite angle is constant
In our case, for the left triangle,
Time to grab a calculator and crunch numbers. Double check your calculator is in degrees and not in radians (plug in sin 30°, if you're getting 0.5 you're good) and you will get
Same difference with the right triangle. With the same calculations
Answer:
<h3>{44-55}</h3><h3>{52- 59 } are the last two interval s</h3>
Step-by-step explanation:
<h2>To get the class boundaries deduct 0.5 from the first number and add 0.5 to the second number = 4-0.5 = 3.5 </h2><h2> = 11.5 + 0.5 = 11.5 </h2><h2> = 3.5 -11.5 as in the fish class boundary .</h2><h2>same for all other boundaries</h2>
